By looking at the problem you've presented it should look like this:
P = [(105000/39.95)(0.08214)(293)]/(50)
P = 1265.1 atm
P = 1.27 x 10^3 atm
I've left out the units for simplicity, but you should write them in yourself.
On second glance, your molar mass for Argon seems to be off, also, you've made a calculation error. Try again and tell me what you got. (I've worked it out this time).
Nope! Your answer is quite reasonable, and it seems like nothing looks wrong in your setup of P= nRT/V and all the units match, your value for R is correct and you've converted C to K. Unless you made a calculating mistake, everything looks correct to me.
I think I've figured it out, It's just like a box on an incline question, however the current is going out of page, resulting in a magnetic force to the right up the ramp.
Well this is what I get:
Fb = BIL(perpendicular)
Fb = 0.5T(70A)(0.12mcos30)
Fb = 3.6373N into the page
Fnet (perpendicular) = Fn - mgcos30
Fn = mgcos30
Fn = (0.1kg)(9.8 N/kg)cos30
Fn = 0.8487N
There's also mgsin30, but I don't know where that goes. This is where I'm stuck.
A steel rod of 0.10kg rests on two metal rails inclined at an angle of 30 degrees. There is a magnetic field of 0.50T on the incline and a current of 70A flowing across the bar. Find the acceleration of the bar.
The bar is 0.12m wide**
The attempt at a solution
What I have so far is a diagram...
Well, one way to think about this is:
If you drop a ball and it hits the ground, you observe that it stops and doesn't go through.
What causes the ball to fall? Gravity
What essentially prevents the ball from going through? The Strong Force, Weak Force and Electromagnetic Force.
By seeing...