Recent content by SpecialKM

This is spot on.

By looking at the problem you've presented it should look like this: P = [(105000/39.95)(0.08214)(293)]/(50) P = 1265.1 atm P = 1.27 x 10^3 atm I've left out the units for simplicity, but you should write them in yourself.

Nono, on the work you've showed in your original post, it looks like you've put 36 g/mol.

On second glance, your molar mass for Argon seems to be off, also, you've made a calculation error. Try again and tell me what you got. (I've worked it out this time).

Nope! Your answer is quite reasonable, and it seems like nothing looks wrong in your setup of P= nRT/V and all the units match, your value for R is correct and you've converted C to K. Unless you made a calculating mistake, everything looks correct to me.

I think I've figured it out, It's just like a box on an incline question, however the current is going out of page, resulting in a magnetic force to the right up the ramp.

Well this is what I get: Fb = BIL(perpendicular) Fb = 0.5T(70A)(0.12mcos30) Fb = 3.6373N into the page Fnet (perpendicular) = Fn - mgcos30 Fn = mgcos30 Fn = (0.1kg)(9.8 N/kg)cos30 Fn = 0.8487N There's also mgsin30, but I don't know where that goes. This is where I'm stuck.

well, what I know is the force of a wire interacting with an external B field. Fb = BIL

anyone ?

Did you convert the 68cm to m?

A steel rod of 0.10kg rests on two metal rails inclined at an angle of 30 degrees. There is a magnetic field of 0.50T on the incline and a current of 70A flowing across the bar. Find the acceleration of the bar. The bar is 0.12m wide** The attempt at a solution What I have so far is a diagram...

Just like God!111

Well, one way to think about this is: If you drop a ball and it hits the ground, you observe that it stops and doesn't go through. What causes the ball to fall? Gravity What essentially prevents the ball from going through? The Strong Force, Weak Force and Electromagnetic Force. By seeing...

We can do what ever we want with it! Well, what I think is that first we take a sample of each and add Ca 2+ ions (CaO) to each, and it should then create a precipitate of CaSO4. After that take additional samples from each and add sulphide ions (Na2S) to then form a precipitate of Ag2S...

There are 3 beakers with solutions inside of the beakers A B and C, however the labels have fallen off! The labels of the solutions are: MgSO4, CaCl2, and AgNO3. Explain the steps you would use to determine which beaker has which solution inside of each of the three beakers...