Identify Solutions in Beakers A, B & C

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To identify the solutions in beakers A, B, and C, one can start by adding calcium ions (Ca2+) to each sample, which will precipitate calcium sulfate (CaSO4) if magnesium sulfate (MgSO4) is present. Next, adding sodium sulfide (Na2S) will help identify silver nitrate (AgNO3) by precipitating silver sulfide (Ag2S). An alternative method for detecting silver involves using a more common reagent, which could simplify the process. The discussion emphasizes the importance of using appropriate reagents to effectively distinguish between the three solutions. Proper identification relies on the formation of specific precipitates from the reactions.
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There are 3 beakers with solutions inside of the beakers A B and C, however the labels have fallen off!

The labels of the solutions are: MgSO4, CaCl2, and AgNO3.

Explain the steps you would use to determine which beaker has which solution inside of each of the three beakers.

_______________________

My first intuition is that you need to precipitate something, I just don't know what. :(
 
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Follow your intuition then.

Are you allowed to use additional reagents, or can you use only the three listed? In the latter case I am not convinced all three solutions can be properly identified.
 
We can do what ever we want with it! Well, what I think is that first we take a sample of each and add Ca 2+ ions (CaO) to each, and it should then create a precipitate of CaSO4. After that take additional samples from each and add sulphide ions (Na2S) to then form a precipitate of Ag2S.

That's what I think, is this correct?
 
CaO as a source of Ca2+? Think it over.

Na2S will work, but silver can be detected much simpler, with much more common reagent.
 
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