Recent content by Stalafin

Landau considers that part for a quantum mechanical system. w_n = w(E_n) is the distribution function for the system. He gets there from the diagonal elements of the density matrix w_n = w_{nn} (since the statistical distributions must be stationary), which can be expressed as functions of...

Question about Landau: Definition of "Number of states with energy" in an interval Hey! I am currently reading Landau's Statistical Physics Part 1, and in Paragraph 7 ("Entropy") I am struggling with a definition. Right before Equation (7.1) he gives the "required number of states with...

I have the following process: q(R) + \bar{q}(\bar{B}) \rightarrow q(R)+\bar{q}(\bar{B}) In words: a quark with red color-charge and an antiquark with an anti-blue color-charge are incoming, and a red quark and anti-blue antiquark are emerging. Since I am not sure how else to draw that, I try...

The curriculum is indeed great! I did see a couple of Indians here and there, but none of them in my program, but since the city is crazy international (feels like you have more tourists at any given time than actual inhabitants) you should be perfectly. Physics Masters are definitely dominated...

I am currently doing my Master's degree at the University of Heidelberg, which located in the same state as Stuttgart. In terms of the quality of education you shouldn't worry too much, as the quality of education is pretty much on a comparable level throughout Germany. Most universities have...

Alright, I am sorry; I was under the impression that the same thing applies to the UK as well. Then again, the statement remains true for main Europe. :-)

If you go to Europe with a Bachelor's only, you will have to do a Master's degree first. There are no exceptions in the field of Physics to my knowledge. Master's degrees are never paid. On the PhD level, that is different. However, good luck finding funding in the UK. From what I can tell...

Okay, the first and the second one are equivalent if I set r=v^2, a=2\boldsymbol{v}\boldsymbol{\varepsilon} and disregard terms \boldsymbol{\varepsilon}^2. I still do not quite see how to get the first equation done properly. For a normal Taylor expansion (up to first order), we have: f(x) =...

I have a question about Taylor expanding functions. For both cases I can't get my head around why things are the way they are. I just don't see how one would perform Taylor expansions like that. The first: The starting point of a symmetry operations is the following expansion: f(r+a) = f(r)...

I thought about making an expansion... This is what I came up with (Peskin expands for epsilon): \left. U(x+\epsilon n,x) \right|_{\epsilon=0} = U(x,x) + U'(x,x) n \epsilon + \mathcal{O}(\epsilon^2) So, U(x,x) becomes one from the zero separation condition; what I have trouble understanding is...

I am trying to understand the derivation of the covariant derivative in Peskin/Schroeder (chapter 15.1, page 483). This is the important stuff: n^\mu\partial_\mu\psi=\lim_{\epsilon \rightarrow 0} \frac{1}{\epsilon}\left[\psi(x+\epsilon n)-\psi(x)\right] Scalar quantity: U(y,x): U(y,x)...

And how did they feel about that?

Since I did not receive any reply yet albeit this post having 62 views, I will put my question differently: 1) Are there any significant advantages of obtaining a PhD first and then going into industry, assuming one would get a job either way? 2) Is it feasible to return to academia having...

Currently I am doing my MSc in Physics with a focus on Condensed Matter Theory. I have about one more year to go, after which I will have to decide how to carry on. By the time I finish my Masters I will be 23 years old. This summer I will do a well-paid internship in the financial sector at...

Hey! Thanks for your reply. Yes, I discussed this with a friend today, and we came to the same conclusion. Thanks!