Recent content by Texag

Thanks for the reply. So, is it just when not under the ideal gas assumption that dU=C_V\,dT for a constant-volume process (only)? Just seemed a little redundant, but if I was missing out on assuming ideal gas, then that explains it. Thanks again.

Homework Statement A gas in a piston-cylinder assembly undergoes a thermodynamic cycle consisting of three processes. Process 1-2: adiabatic compression with pV1.4 = constant from p*1 = 50 psia and V1 = 3 ft3 to V2 = 1 ft3. Process 2-3: isometric, Process 3-1: isobaric with U*1 - U*3 =...

Not exactly essential guy films, but the marx brothers movies are absolutely hilarious. Kinda like the three stooges but more intellectual.

You have to be sure to change the initial velocity each time you calculate. For example, when finding the displacement of the second portion, It is not zero, but the final velocity of the one you calculated above.

You know that charge cannot flow between the capacitors, so the charges on them are equal.

Use this equation: x = (1/2)*a*t^2 +Vi*t + Xi And, a horizontal line is constant acceleration, A line horizontal at Zero is zero acceleration.

Work Energy theorem. Work done equals energy. (Force)x(Distance)= 1/2 (mass)(velocity)^2. Take mass out of each side of the equation. You have this written already, just apply it. Under constant acceleration, Velocity equals acceleration x time.

The Departed is a good modern classic.

When you are in legitimate need of the resources.

Here's how you go about it. For a Gaussian surface, recall that the total flux out of any closed surface is known if you know the charge. You must also find the individual electric flux through each face of the cube by integrating. Then you have the total flux with "b" in it which is equal to...

You know the initial velocity is your variable, you know the constant force in the y direction, and no force in the x direction. It is akin to a projectile motion problem...

Yes, its the one by McMahon. I read through the first chapter, and after I noticed a few mistakes (he switched current density and charge density at one point) I am deciding to try to return the book, also It only had a small review on SR, which I have yet to grasp. I will be returning to the...

This may help: Use the formulas for the amount of potential energy in the spring at a certain distance, then equate that with the kinetic energy of the spring once it has left, this will give you the velocity related to the stretch in the spring.

First of all, The coefficient of friction you have is for static friction. Secondly, you must account for the entire system's mass since they are all accelerating.

Q1: I am guessing something is dropped from 52m, The potential energy at the top is equal to the kinetic at the bottom. You should have expressions that give you the value for each. Q2: Period is the time you add to go from one position, back to the position again. Units are in time per...