Recent content by TheColector

Hi there I'm having a hard time trying to understand how come ∂r^/∂Φ = Φ^ ,∂Φ/∂Φ = -r^ -> these 2 are properties that lead to general formula. I've been thinking about it and I couldn't explain it. I understand every step of "how to get Divergence of a vector function in Cylindrical...

Thanks a lot That is a nice way of putting it.

I generally know the meaning of extremum and that is either min or max depending on a change of sign, the thing I HAD problem with was to show existence of the extremum using derivative only without wider analysis (such as decreasing value of function). I was pretty confused about all of it...

I can say that f(x) is decreasing in the domain of f'(x) as it is < 0. So I can expect the min value to be at the end point of the domain but I don't exactly know why the min value exists since the conditions for them to be are not met. That is what I have problem with, not exactly finding min...

Domain is {-1 < x <= 1} - considering f(x) when considering the domain of f'(x) it is the same but without point of 1 I guess that means there is no derivative at that point, as it goes to (- infinity) there.

Yes I did and there is obvious min of f(x) for x = 1, but how can this be that the conditions for finding the extremum of function are not met, yet there is the extremum at that point. Is it maybe because f(x) is not differentiable at point x = 1 ?

Oh gosh Sorry for that mistake. I entered wrong function. It should be sqrt((1-x)/(1+x)) The statements I posted describe function above. Sorry for that stupid mistake of mine

Homework Statement Hi I'm having a trouble with finding min value of given function: f(x) = sqrt((1+x)/(1-x)) using derivative.First derivative has no solutions and it is < 0 for {-1 < x < 1} when f(x) is given for {-1 < x <= 1}. For x = - 1 there is a vertical asymptote and f(x) goes to +...

@kuruman Yeah that seems to be correct. Thanks for your help. Take care

It was indeed about calculating magnitude of the unit vector. In order to use radial velocity I assume that given motion is a circular one I might have actually mislead you in the description. I'm to prove that v^ has magnitude(which I did) , turn and direction) The thing is I have no idea why...

Homework Statement Hi Given the linear velocity formula: v* v^ = r*ω(-sinθi^ + cosθj^) i^, j^, v^ - unit vectors I'm to prove that v^ has direction, turn and magnitude Magnitude: |v^| = sqrt((-sinθ)^2 + (cosθ)^2) = 1 (as is also stated in unit vector's definition) Direction and turn...

Sorry about deleting it. I won't do so in the future. What I meant with this → was to show the represenstative form of x and iy as a part of "z"

Hi I was hoping some of you would give me a clue on how to solve this complex number task. z = (1 +(√3 /2) + i/2)^24 → x=(1 +(√3 /2), y= 1/2 I think there must be some nice looking way to solve it. My way was to calculate |z| which was equal to [√(3+2√3)]/2 → cosθ = x/|z|, sinθ= y/|z| After...

Much appreciated THANKS !

That was actually the first circuit. The one I had problem with was its upgrade :D