Thank you for the quick response Dr. D!
So in that case, could I choose a function (like before):
φi(x) = 1 - cos(2πix/L), i = 1,2,3,...
φj(x) = 1 - cos(2πjx/L), j = 1,2,3,...
Where they would end up being
φ1(x) = 1 - cos(2πx/L)
φ2(x) = 1 - cos(4πx/L)
φ3(x) = 1 - cos(6πx/L)...
Thank you!