Transfer Function of Block Diagram

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SUMMARY

The discussion centers on deriving the transfer function for a PM DC servo motor with current loop feedback. The transfer function is approximated as G(s) = (1/Kb) / (τms + 1)(τes + 1), where τm = J(R + Ki) / KTKb and τe = L / (R + Ki). Participants attempted to simplify the block diagram and factor the denominator using the quadratic formula but struggled to match the expected form. The consensus indicates that the approximation is valid under the condition J(Ki + R)² >> 4KTKbL.

PREREQUISITES
  • Understanding of transfer functions in control systems
  • Familiarity with PM DC servo motor dynamics
  • Knowledge of quadratic equations and their applications in system analysis
  • Experience with block diagram simplification techniques
NEXT STEPS
  • Study the derivation of transfer functions for different types of motors
  • Learn about the implications of feedback loops in control systems
  • Explore the use of MATLAB for simulating servo motor dynamics
  • Investigate the effects of varying Ki on system stability and performance
USEFUL FOR

Electrical engineers, control system designers, and students studying servo motor dynamics will benefit from this discussion, particularly those focused on transfer function analysis and feedback control systems.

ThLiOp
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Homework Statement


The block diagram of a PM DC servo motor with current loop feedback is shown below:

QWERTY.jpg


If Ki is adjusted such that J(Ki+R)2 >> 4KTKbL, show that the transfer function may be approximated by

G(s) = (1/Kb) / (τms+1)(τes+1),

where

τm = J(R+Ki) / KTKb

τe = L / (R+Ki)

The Attempt at a Solution


[/B]
I simplified the block diagram and got the transfer function:

G(s) = Kt / (JLs2 + J(R + Ki)s + KtKb)

Then I tried to factor the denominator. When using the quadratic formula, I found:

(-JR - JKi) +/- sqrt( J[ J(R+Ki)2 - 4KtKbL]) / 2JL

Assuming the conditions presented for Ki, I canceled out the 4KtKbL.

Am I on the right path? In the end, I still couldn't get the transfer function presented in the homework.
 
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ThLiOp said:
I simplified the block diagram and got the transfer function:

G(s) = Kt / (JLs2 + J(R + Ki)s + KtKb)
That seems fine.

ThLiOp said:
Then I tried to factor the denominator. When using the quadratic formula, I found:

(-JR - JKi) +/- sqrt( J[ J(R+Ki)2 - 4KtKbL]) / 2JL
Those are just the roots, though. If ##ax^2 + bx + c## is your polynomial, then its factored form is ##a(x - x_1)(x - x_2)##, where ##x_1## and ##x_2## are its roots.

ThLiOp said:
Am I on the right path? In the end, I still couldn't get the transfer function presented in the homework.
I can't either. Going your route, and I think the approximation shown is highly suggestive of that, I get the form:
$$
\frac{\dot{\theta}(s)}{V(s)} = \frac{\frac{1}{K_b}}{\tau_m s (\tau_e s + 1)}
$$
Sort of looks like a typo, but maybe there's another route I'm just not seeing.
 

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