Singularities of a Complex Function

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SUMMARY

The discussion focuses on identifying the singularities of the complex function defined by the equation 1/[z²(z³+2)] = 1/z³ - 1/(6z) + 4/z¹⁰. The singularities occur when the denominator z²(z³+2) equals zero, leading to z = 0 and z³ + 2 = 0. The solution for z³ + 2 results in z³ = -2, which can be expressed in polar form as r³e^(i3θ). The absolute value of z³ is calculated as r = |z³| = 2, confirming the magnitude of the singularity.

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  • Understanding of complex functions and their singularities
  • Familiarity with polar coordinates and Euler's formula
  • Knowledge of algebraic manipulation of complex numbers
  • Basic calculus concepts related to function expansion
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Students and professionals in mathematics, particularly those studying complex analysis, as well as educators seeking to enhance their understanding of singularities in complex functions.

ThLiOp
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Homework Statement



What are the region of validity of the following?

1/[z2(z3+2)] = 1/z3 - 1/(6z) +4/z10

Homework Equations

The Attempt at a Solution



Knowing that this is the expansion around z=0, I am trying to find the singularities of the complex function.

Which is when z2(z3+2) = 0

I have z = 0, then (z3+2) = 0

(z3+2) = 0

z3 = -2 = r3ei3θ

In order to find r, would I take the absolute value of z3?

r = |z3| = |-2| = sqrt[(-2)2] = 2?
 
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ThLiOp said:
r = |z3|
I don't think that's what you meant. Try again.
 

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