- #1
ThLiOp
- 9
- 0
Hi everyone,
I'm having a bit of difficulty choosing an admissible function for a fixed-fixed nonuniform bar.
I chose the function φ(x) = 1 - cos(2πx/L).
But when solving for the the stiffness and mass coefficients:
kij = ∫EA(x)φiφjdx
mij = ∫ρ(x)φiφjdx,
I am not sure where I should have the "i" and "j" in my function.
In an example for a fixed-free beam, the function that was given was:
φ(x) = sin(πx/2L), which was changed to φi(x) = sin[((2i-1)πx)/2L].
Should I choose my function to be φi(x) = 1 - cos(2πix/L)? And why?
I'm having a bit of difficulty choosing an admissible function for a fixed-fixed nonuniform bar.
I chose the function φ(x) = 1 - cos(2πx/L).
But when solving for the the stiffness and mass coefficients:
kij = ∫EA(x)φiφjdx
mij = ∫ρ(x)φiφjdx,
I am not sure where I should have the "i" and "j" in my function.
In an example for a fixed-free beam, the function that was given was:
φ(x) = sin(πx/2L), which was changed to φi(x) = sin[((2i-1)πx)/2L].
Should I choose my function to be φi(x) = 1 - cos(2πix/L)? And why?