Recent content by totallyclone

So I have to separate them to their own X and Y components??

Homework Statement Consider point a which is 65 cm noth of a -2.8μC point charge, and point b which is 80 cm west of the charge. Determine (a) Vba=Vb-Va, and (b) Eb-Ea (magnitude and direction)Homework Equations k=9x10-9 V=kQ/r V=kQ(1/rb-1/ra) E=kQ/r2 E=kQ(1/rb2-1/ra2)The Attempt at a Solution...

so...THERE'S FRICTION!?

I find this question tricky because maybe I'm overthinking it... I think the external force would be what the dog applies. Then suddenly stopping, transfers the energy to the raft causing it to more forward towards the shore?

Homework Statement A dog of mass 10.0kg is standing on a raft so that he is 20.0m from shore. He walks 8.00m along the raft towards shore and then halts. The raft has a mass of 40.0kg, and we can assume there is no friction between the raft and the water. How far is the dog from shore when he...

Homework Statement A bicyclist coasts down a 7.0° hill at a steady speed of 5.0m/s. Assuming a total mass of 75kg (bicycle plus rider), what must be the cyclist's power output to climb the same hill at the same speed? Homework Equations EK=1/2 mv2 EG=mgh P=W/T The Attempt at a...

...right. Yeah, I do remember there's a way to determine how many significant figures one should use. For example, if the given is in 3 significant figures, the suggested answer should be more than 3 significant figures, maybe 4 or even 5. Anyways, thank you so much for your help on this...

What would you suggest I leave the answers in how many significant figures?

WNET=EKf-EKi WNET=-1/2 mv2 eqn.1 WNET=FfΔdcos180°+Fg||Δdcos180° -1/2 mv2=FfΔdcos180°+Fg||Δdcos180° subbed eqn.1 v=√-2(FfΔdcos180°+Fg||Δdcos180°)/m v=18.9m/s v=68.0km/h I think this makes sense that the speed is more than the speed it would take without the snow now that there is...

So there is an applied for by the engine and a force of friction, then they should both be the same values since they oppose each other. Also, I realized my calculator was in rad when I calculated the angle of the driveway no wonder it was sooo small. I corrected the angle to be 13.0°. My...

In the question, it says "...drives an ideal frictionless car...". So, apparently, there is a force of friction??

Coasting up a driveway with snow -- cons. of energy Homework Statement Your Physics teacher drives an ideal frictionless car of mass 1000kg which coasts along the level road to his home at a constant speed of 48km/h with the engine turned off. It then coats up 40m his sloping driveway and...

Volume of B=4/3 ∏r3 =4/3∏(2rA)3 =4/3∏(8rA3) =8(4/3∏rA3) =8 volume of A So, planet B's volume is 8 times of A's...

So I doubled the radius. I didn't notice their densities would be the same since they're made of the same material. Anyways: EKA=-1/2 EGA 1/2 mvA2=-1/2(-GmMA/rA) vA2=GMA/rA and EKB=-1/2 EGB 1/2 mvB2=-1/2(-GmMB/2rA) vB2=GMB/2rA

OOH, so the distance the question is called the arc length? Didn't know that! So, if I used that formula: angle (in rad) x radius = arc length arc length = (48 x ∏/180) x 125 arc length = 105m So the total distance Mike Harris travels on the sky dome rooftop is 105m? :smile: