Electric Potential and Electric Energy

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Homework Help Overview

The discussion revolves around calculating electric potential and electric field differences between two points in relation to a point charge. The specific points are defined in relation to a -2.8μC charge, with one point located 65 cm north and the other 80 cm west of the charge.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculations for electric potential and electric field differences, questioning the correctness of their results and the interpretation of directionality, particularly regarding vector subtraction.

Discussion Status

Some participants have provided calculations for the electric potential and electric field differences, while others have raised questions about the vector nature of electric fields and the need to resolve them into components. There is an ongoing exploration of the correct approach to handle vector subtraction.

Contextual Notes

Participants express uncertainty about the direction of the electric field due to the negative magnitude obtained in their calculations. There is also a mention of needing to separate the electric fields into their respective X and Y components for proper vector subtraction.

totallyclone
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Homework Statement


Consider point a which is 65 cm noth of a -2.8μC point charge, and point b which is 80 cm west of the charge. Determine (a) Vba=Vb-Va, and (b) Eb-Ea (magnitude and direction)

Homework Equations


k=9x10-9
V=kQ/r
V=kQ(1/rb-1/ra)
E=kQ/r2
E=kQ(1/rb2-1/ra2)

The Attempt at a Solution


(a) Vba=Vb-Va
=kQ(1/rb-1/ra)
=(9x10-9)(-2.8x10-6)(1/0.8-1/0.65)
=7.269x10-15 V

(b) Eb-Ea
=kQ(1/rb2-1/ra2)
=(9x10-9)(-2.8x10-6)(1/0.82-1/0.652)
=2.027x10-14 N/C

I may have mistakes. I wonder if it's right. So I found the magnitude for (b) but I'm not quite sure about the direction (since it has a negative magnitude)? :shy:
 
Last edited:
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totallyclone said:
(b) Eb-Ea
=kQ(1/rb2-1/ra2)
=(9x10-9)(-2.8x10-6)(1/0.82-1/0.652)
=2.027x10-14 N/C

I may have mistakes. I wonder if it's right. So I found the magnitude for (b) but I'm not quite sure about the direction (since it has a negative magnitude)? :shy:
Realize that Eb and Ea are vectors. You must subtract them as vectors.
 
So I have to separate them to their own X and Y components??
 
totallyclone said:
So I have to separate them to their own X and Y components??
Sure, that's one way of doing it.
 

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