Electric Potential and Electric Energy

totallyclone
Messages
54
Reaction score
0

Homework Statement


Consider point a which is 65 cm noth of a -2.8μC point charge, and point b which is 80 cm west of the charge. Determine (a) Vba=Vb-Va, and (b) Eb-Ea (magnitude and direction)

Homework Equations


k=9x10-9
V=kQ/r
V=kQ(1/rb-1/ra)
E=kQ/r2
E=kQ(1/rb2-1/ra2)

The Attempt at a Solution


(a) Vba=Vb-Va
=kQ(1/rb-1/ra)
=(9x10-9)(-2.8x10-6)(1/0.8-1/0.65)
=7.269x10-15 V

(b) Eb-Ea
=kQ(1/rb2-1/ra2)
=(9x10-9)(-2.8x10-6)(1/0.82-1/0.652)
=2.027x10-14 N/C

I may have mistakes. I wonder if it's right. So I found the magnitude for (b) but I'm not quite sure about the direction (since it has a negative magnitude)? :shy:
 
Last edited:
on Phys.org
totallyclone said:
(b) Eb-Ea
=kQ(1/rb2-1/ra2)
=(9x10-9)(-2.8x10-6)(1/0.82-1/0.652)
=2.027x10-14 N/C

I may have mistakes. I wonder if it's right. So I found the magnitude for (b) but I'm not quite sure about the direction (since it has a negative magnitude)? :shy:
Realize that Eb and Ea are vectors. You must subtract them as vectors.
 
So I have to separate them to their own X and Y components??
 
totallyclone said:
So I have to separate them to their own X and Y components??
Sure, that's one way of doing it.
 

Similar threads

Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 22 ·
Replies
22
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
4K