Recent content by vinamas

Sure for part a) B=(mu0*mu)/(2piz^3) = (10^-7*2*8*10^22)/(6371 x 10^3)^3 = 6.2 x 10^-5 T part b) mu=AI , 8x10^22=(pi*(6371x 10^3)^2)(I) solve for I=6.28 x 10^8

So I'm mainly having trouble with part b as I have successfully completed part a. In part b I get an answer of 6.3 x 10 ^8 Amperes which my homework tool flags as incorrect. I'm clueless as to where to go from there or why my approach is wrong?

1. The problem statement, all variables Use this photo http://m.imgur.com/a/lQd9q Two masses are connected to two pulleys via ropes.The mass of the hung mass is 16kg and the mass of the object on the slope is 8kg the slope has an angle of 37 degrees. Pulleys 1 has a mas of 6 kg and Pulley 2...

Homework Statement A rock is thrown from a cliff that is 50m long with an initial velocity of 7m/s and an angle of 53, find the rock's veloctity before it hits the ground Homework Equations vfy=sin(theta)*vi-gt vf^2=(vi*sin(theta))^2-2gy The Attempt at a Solution x=vi*cos()t t=x/(vi*cos)...

Homework Statement [/B] A girl is heading home riding her bike she notices a giant wooden log is blocking the road 42m away. If the friction coefficient between her bike tires and the road is 0.36 and she is driving at 25km/h,then what is the distance required for her to stop given that the...

Thank you very much but I made a mistake 2cm is the radius not the diameter thanks!

Homework Statement The following image shows the parts A and B of a pipe where the middle part goes under a hill the length of both parts A and B is 30m and the diameter of them each is 2cm where as the middle part has a length of 110m to determine the middle part's diameter one engineer...

well after hours of crying and thinking why did I go into the advanced high school program I think I've found the answer and it goes like this FBwater+FBoil-Fg=0 1000*0.04*0.04*L*9.81+930*(0.04-h)*0.04*0.04*9.81-0.602=0 L=0.0171 m. I feel good now btw

What am I required to change?I think that FBwater is correct and the mass of the cube is correct too I can also obtain the volume of of the part of the cube in oil but I don't know what to do with it

nope

The closest thing on my mins is Fnet=FBwater+FBoil-Fgcube=0 but that still doesn't get me the answer

well I have seen the problem again and am sorry because I translated it wrong it doesn't say half it just says the lower surface is in water and the upper surface is in oil

Homework Statement A layer of oil that has a density of 930kg/m^3 is floating on the surface of water in a container if a wooden cube with a length of 4 cm becomes submerged where it's lower half is in water and it's upper half is in oil the cube's density is 960kg/m^3 find A) the buoyancy...

oh wait I totally get you now so 0.0007=0.1*0.1*L and L = 0.07 m thank you!

I don' I don't get what you mean I was trying to get the volume of the submerged part by doing that is the volume correct?