How Do You Calculate the Final Velocity of a Projectile?

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SUMMARY

The final velocity of a projectile can be calculated using the equations of motion under gravity. In this discussion, a rock is thrown from a 50m cliff with an initial velocity of 7m/s at an angle of 53 degrees. The relevant equations include vfy = sin(theta) * vi - gt and vf^2 = (vi * sin(theta))^2 - 2gy. The correct approach involves determining the time of flight and correctly applying the equations to find the final velocity, which should yield a result of 32 m/s.

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  • Understanding of projectile motion principles
  • Familiarity with trigonometric functions (sine and cosine)
  • Knowledge of kinematic equations
  • Basic algebra for solving equations
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  • Learn about the impact of angle on projectile trajectories
  • Explore the concept of time of flight in projectile motion
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Homework Statement


A rock is thrown from a cliff that is 50m long with an initial velocity of 7m/s and an angle of 53, find the rock's veloctity before it hits the ground

Homework Equations


vfy=sin(theta)*vi-gt
vf^2=(vi*sin(theta))^2-2gy

The Attempt at a Solution


x=vi*cos()t
t=x/(vi*cos)
x=7*cos(53)-2*9.81*(x/(vi*cos(53)))^2
x =2.49 or x=-6.11
at this point i tried to plug in x into vf^2=(vicos)^2-2gy
but none of them give 32 m/s which is the answer according to the answer's sheet
 
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Some questions for you to consider:
In your solution what is x? It appears you are using x to represent two different quantities.
Why do you think the time of flight is given by your second equation?
 

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