Earth's magnetic dipole homework problem

  • Thread starter vinamas
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  • #1
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Homework Statement:

The earth's magnetic dipole is 8.0×10^22Am2
a)What is the magnetic field strength on the surface of the earth at the earth's north magnetic pole? You can assume that the current loop is deep inside the earth. Ans=6.25x10^-5 T


b)Astronauts discover an earth-size planet without a magnetic field. To create a magnetic field at the north pole with the same strength as earth’s, they propose running a current through a wire around the equator. What size current would be needed?

Relevant Equations:

B=(mu0*mu)/(2piz^3)
mu=AI A=Area , I = current
So I'm mainly having trouble with part b as I have successfully completed part a. In part b I get an answer of 6.3 x 10 ^8 Amperes which my homework tool flags as incorrect. I'm clueless as to where to go from there or why my approach is wrong?
 

Answers and Replies

  • #2
berkeman
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Can you show your calculations for both parts please? Thanks.
 
  • #3
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Sure for part a) B=(mu0*mu)/(2piz^3) = (10^-7*2*8*10^22)/(6371 x 10^3)^3 = 6.2 x 10^-5 T
part b) mu=AI , 8x10^22=(pi*(6371x 10^3)^2)(I) solve for I=6.28 x 10^8
 

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