Two pulleys and two masses on a slope

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SUMMARY

The discussion focuses on solving a physics problem involving two pulleys and two masses on a slope. The masses are 16 kg (hanging) and 8 kg (on the slope), with pulleys weighing 6 kg and 4 kg, respectively, and the slope angle is 37 degrees. The kinetic friction coefficient is given as 0.23. Key calculations include determining the angular acceleration of the pulleys, the linear acceleration for each pulley, and the tension forces in the ropes. Participants emphasize the importance of clearly defining variables and using proper notation for clarity in problem-solving.

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  • Understanding of Newton's laws of motion
  • Familiarity with torque and angular acceleration concepts
  • Knowledge of friction coefficients and their application
  • Ability to use LaTeX for mathematical expressions
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  • Learn how to calculate angular acceleration using torque and moment of inertia
  • Study the principles of tension in ropes connected to pulleys
  • Explore the effects of friction on motion in inclined planes
  • Practice using LaTeX for formatting complex equations in physics
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for problem-solving strategies in pulley systems and inclined planes.

vinamas
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1. The problem statement, all variables
Use this photo
http://m.imgur.com/a/lQd9q

Two masses are connected to two pulleys via ropes.The mass of the hung mass is 16kg and the mass of the object on the slope is 8kg the slope has an angle of 37 degrees. Pulleys 1 has a mas of 6 kg and Pulley 2 has a mass of 4 kg. using the picture and the given info find the following (the kinetic friction coefficient is 0.23)
a) Angular acceleration for the two pulleys
b) the linear acceleration for each pulley
c) the force of each of the ropes that are connected to the pulley

Homework Equations


angularacceleration=a/r
Torque=F.r
angularacceleration=Torque/I

The Attempt at a Solution


angularacceleration=torque/i
((m1g-Ft1)r1-(-Fk-m2g×sin37+Ft2)r2)/(0.5)(6)(0.15)^2+(0.5)(4)(0.1)^2
as you can see I already have 3 variables what should i do?
 
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You should provide a better image, one that is oriented properly, or describe the pulley arrangement in better detail in your text. It's preferable to upload images to PF rather than to some off-site storage area.
 
vinamas said:
((m1g-Ft1)r1-(-Fk-m2g×sin37+Ft2)r2)/(0.5)(6)(0.15)^2+(0.5)(4)(0.1)^2
That is very hard to decipher. The reader has to reverse-engineer the expressions to figure out what all the variables are and what the numbers represent.
Either use LaTeX or, at the least, use the superscript and subscript buttons provided.
Define all your variables. For the constants, it is better to invent and define variables to represent them, only plugging in numbers at the end. (This has many advantages.) if you must plug in numbers straight away, build the expression up in steps, explaining what you are doing.
 
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