Recent content by whereitsbeen

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    Allowable load in short compression member

    for b, I get 21600 x 317 = 68.5 which is good for a, I get 21600 x 5.53 = 119.4 which is no good
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    Allowable load in short compression member

    My apologies, I don't own a scanner or else I would show the 200 variations of formulas I've played around (my work) with all day to get these answers. Question is this; A short compression member is fabricated from 2 steel pipes. the pipe on the top has a cross sectional area of 3.17 in sq...
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    Are Your Moment Calculations for Bent Bar Reactions Correct?

    Calculate the internal reactions for the member shown at the sections indicated; picture attached with FBD's I have the V & F forces correct but my moments are off. Can you point me in the right direction here? V M-M = 2k F M-M =-0.5k V N-N = -2k F N-N = 0.5k M M-M = -10k (2) +...
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    STATICS truss/ math equation - joint by joint

    studying for my test, I have a truss joint equation with 2 variables ƩFx = 0 : 4/15 (15kN) - 10/10.44(Fbd) - 4/5(Fbe) = 0 12 = .957(Fbd) + .8(Fbe) ƩFy= 0 : 3/5 (15kN) - 6kN - 3/10.44(Fbd) + 3/5(Fbe) = 0 6 = 9 -.287(Fbd) + .6(Fbe) -3 = .287(Fbd) + .6(Fbe) this is where I'm...
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    How Does a Motorcycle Exert Force Backward to Accelerate?

    Thank You
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    How Does a Motorcycle Exert Force Backward to Accelerate?

    Homework Statement A 245 kg motorcyle & rider can produce an acceleration of 3.50 m/s sq while traveling at 25 m/s. At that speed, the forces resisting motion (friction & air) total 400 N. What force does the motorcycle exert backward to produce it's acceleration? Homework Equations...