Recent content by yashboi123

Hello. I was wondering why do we not multiply cos(alpha) by 2. I believe we should do this since the y-components of the electric field cancel out, meaning there would be 2 x-components of the electric field(at least I think so). Currently, this derivation/answer only considers one horizontal...

I'm curious as to why the average power is not negative in this scenario, since I thought the friction force is in the opposite direction of velocity. As far as I see friction force is the only acting force in the problem, but I may be wrong. I solved this by simply doing (Friction Force *...

I was just wondering why you would do mB * a to get the force A is exerting on B instead of mA * a

Thanks mate, that was a dumb mistake from me it's pretty clear since D is below C the vertical component of Tc wouldn't be considered.

Is my thought process correct here?

It would be tension upward(or normal force since they are equivalent in this situation) and mg downward. I suppose then they wouldn't be equivalent since in this situation we only take into account mg, not the vertical tension in cable C since cable D is below that point.

No it's not a part C, I'm just curious lol promise. Here is the full page

I found the tension of cable B by doing mg + Csin(37.1). I found C by doing 757(Tension in cable A) = Ccos(37.1). I was just wondering if the tension in cable D is equivalent to the tension in cable B. If possible please show the steps on how you determined if they are equivalent or not. Thank you!

Not sure what r would be in this scenario. I tried adding the radius of the earth to the altitude but that wasn't correct either.

Would greatly appreciate an explanation on this question, not sure I even understand what they're asking.

That's why I asked the question

What else should I say.

Haha I thought we would have to find the acceleration ourselves then solve

I see, thank you.

so essentially relative to water means that speed is constant, in turn causing there to be no acceleration for the east direction. But why can we just assume the river has no acceleration?