Force exerted on block B by Block A when being pushed on a frictionless surface

In summary, when Block A pushes Block B on a frictionless surface, the force exerted by Block A on Block B is equal to the mass of Block B multiplied by its acceleration, according to Newton's second law of motion. Since there is no friction, the only force acting on Block B is the push from Block A, resulting in Block B accelerating in the same direction as Block A.
  • #1
yashboi123
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Homework Statement
Boxes A and B are in contact on a horizontal, frictionless surface (Figure 1). Box A has mass 25.0 kg and box B has mass 7.0 kg . A horizontal force of 100 N is exerted on box A \.
Relevant Equations
F = ma
I was just wondering why you would do
mB * a
to get the force A is exerting on B instead of
mA * a

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  • #2
If B were not there, would there be any force on that side of A? If B was super small, would it take much force to keep it accelerating along with A? What if it was very large? So, you see, B’s inertia is the reason there is any force between B and A and B’s mass is what you need to figure out how big the force is.
 
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  • #3
In problems like this always draw the free body diagrams and show the forces on each block separately. Then you can write the equations and they should makes sense.
 
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  • #4
yashboi123 said:
why you would do
mB * a
to get the force A is exerting on B instead of
mA * a
Because A's acceleration is a consequence of the two forces on A, whereas there is only one force on B.
 
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