Recent content by zeshkani1985

To calculate the volume of the contents you use the formula for a cone, as long as the height of the product, h, is less than or equal to the height of the conical section, hcone. V=1/3rh2h if h ≤ hcone and rh is the radius at height h: rh=tan∅ if rh ≤ R. If the height of the stored...

okay here i did it again since i know that his displacement was .60km due south and the river is 1km wide so to balance it out he had to go .60km due north to cross directly and i took the inverse tan of .60km/1km to get 30.96 which is about 31 degrees i think i might just give up

\*****/each wire here has 5N of tension *\***/ 60 \*/45degress ***| ***| ***| ***? what the weight here?

horizontal

How do you solve for tension, is there a general formula to use for emample such as this problem(this is not homework, its an example i saw ) you have 2 wires one at 60degrees one at 45degrees both wires have a weight of 5N. find the weight of the third wire that's going down? how does...

i think i got it the angle should be 31 degrees i used this and back substituted it and found out that is had to b e 31 degrees.

okay i did set it up how you said so here is my question, i' am just kind a really confused over it i will be using sin, since i know the opposite and hypotenuse since the opposite it 6km/h for the hypotenuse do i use the 10km/h or the 11.6km/hr from the previous answer if i just use the 6/10 i...

i just looked at the problem again and i set it up differently and i took the inverse tan and I got a 5.7 degrees, but since this is just the angle, would you add the 180+5.7 to get 185.7 ?

for the second part in question 2 can i just take the inverse of cos of the distance of the river/by the boat speed cos=1/10=85 degrees

okay since the boat velocity is at 10km/h, and the river at 6km/h 6km/h __ | / 10km/h|/ since there are 2 velocities, 102+62=11.6km/h that's the diagonal speed so with this i can just divide the distance of 1km/10km/h =t to get time and multiply velocity by time to get the...

okay i think i got it, so the plane is acutally 12m above the building, if this is the case, then there is an extra 12m

so it would be 540m-12m = 528m ?

Ok I had these 3 questions: I believe I have ansered the first 2 but I' am just stuck on the third. 1. an aircraft has a glide ratio of 12 to1 m, a building that is 45m high lies directly in the glide path, the plane clears the building by 12m, how far is the run way from the building? ANS: I...

Calculate the density of NaCl at 20C in lbm/ft3 ? since no volume was given i was wondering if this can be done this way by using the Specific gravity which around 2.1x the referance density of solids/liquids which is 62 lbm/ft3 SG=p x pref or can this be done using the PV=nRT, i...