Tension: 2 wires one at 60degrees one at 45degrees

  • Thread starter Thread starter zeshkani1985
  • Start date Start date
  • Tags Tags
    Tension Wires
Click For Summary

Homework Help Overview

The discussion revolves around a problem involving two wires at angles of 60 degrees and 45 degrees, each with a weight of 5N, and a third wire whose weight needs to be determined. Participants explore the relationships between the tensions in the wires and the forces acting on them.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the ambiguity of the problem statement, particularly regarding the reference of the angles and whether the wires are under tension or carrying weights. There are attempts to establish equations based on the forces involved, but confusion arises about the setup and assumptions.

Discussion Status

The conversation is ongoing, with participants questioning the clarity of the problem and the assumptions made about the angles and the nature of the wires. Some guidance has been offered regarding the need to find the resultant force from the upper wires, but no consensus has been reached on the interpretation of the problem.

Contextual Notes

There are indications that the original problem statement may lack critical information, leading to varying interpretations of the scenario. Participants note the inconsistency in assuming the third wire's orientation and the nature of the weights involved.

zeshkani1985
Messages
15
Reaction score
0
How do you solve for tension, is there a general formula to use

for emample such as this problem(this is not homework, its an example i saw )

you have 2 wires one at 60degrees one at 45degrees both wires have a weight of 5N. find the weight of the third wire that's going down?

how does one approach such a problem

I tired doing this , this way, but i' am wrong since the right answer is 6.1N

1. ||a||5Ncos60=||b||5Ncos45
2. ||a||5sin60+||b||5sin45=c

I substituted equation one into 2 and i got 6.9N
 
Physics news on Phys.org
Your problem statement is a bit confusing. For example, the reference of the angles is ambiguous. Are the angles measured with respect to the vertical or horizontal?
 
Do you mean the wires have a tension of 5N?
 
horizontal
 
\*****/each wire here has 5N of tension
*\***/
60 \*/45degress
***|
***|
***|
***? what the weight here?
 
Your third wire cannot be vertical. All you need to do is find the resultant force from the upper two wires. The force from the third must balance that.
 
haruspex said:
Your third wire cannot be vertical.

But if we're talking wires, it pretty much has to be vertical. I think something is missing from the statement of the problem.
 
tms said:
But if we're talking wires, it pretty much has to be vertical. I think something is missing from the statement of the problem.
If we're talking hanging weights it has to be vertical, but then the provided information would be inconsistent. I'd say we're just talking tensions, so the wire can be any angle.
 
haruspex said:
If we're talking hanging weights it has to be vertical, but then the provided information would be inconsistent. I'd say we're just talking tensions, so the wire can be any angle.

But the third wire is just a hanging weight, according to the information given by the OP. I see what you mean, though, about assuming that the third wire is connected somewhere; the OP could have misunderstood the actual problem, or I could have read too much into the given information.
 
  • #10
tms said:
But the third wire is just a hanging weight, according to the information given by the OP. I see what you mean, though, about assuming that the third wire is connected somewhere; the OP could have misunderstood the actual problem, or I could have read too much into the given information.
All three were described as 'having a weight' (not, e.g., 'having a weight attached'). So I feel the most likely intended meaning is that each has a tension.
 
  • #11
haruspex said:
All three were described as 'having a weight' (not, e.g., 'having a weight attached'). So I feel the most likely intended meaning is that each has a tension.

You're probably right.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
5K
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
4K
Replies
2
Views
1K
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
17
Views
3K