Ratio of Copper Valencies in Oxides

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Discussion Overview

The discussion revolves around the valencies of copper in its oxides, specifically addressing a problem related to the ratio of copper valencies in two different copper oxides. Participants explore the implications of the amount of oxygen used in forming these oxides and reference rules related to chemical compounds.

Discussion Character

  • Homework-related
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents a homework problem regarding the ratio of copper valencies in two oxides, noting that twice as much oxygen is used for one oxide compared to the other.
  • Another participant suggests that understanding the meaning of "valency" is crucial for solving the problem and questions whether the specific copper oxides are known.
  • Some participants assert that copper exists in two states, Cu+2 and Cu+1, proposing a valency ratio of 2:1 based on the information provided in a book.
  • There is a discussion about the significance of using "twice as much oxygen" in determining the valency ratio, with differing opinions on its relevance.
  • One participant introduces "Rule 6" from a textbook, which states a relationship between moles of elements in a compound, but there is confusion about its interpretation and derivation.
  • Another participant questions the validity of the rule and suggests it may be a typo, proposing an alternative interpretation related to the definition of a mole.
  • There is a mention of the neutrality of molecules in terms of charge, using Fe2O3 as an example to illustrate the relationship between valency and mole ratios.
  • Some participants express uncertainty about the derivation of the rule and seek clarification on how to prove it.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the significance of the "twice as much oxygen" statement or the interpretation of "Rule 6." Multiple competing views on the valency ratio and the rule's validity remain unresolved.

Contextual Notes

There are limitations in understanding the assumptions behind the rule and the definitions being used. The discussion reflects varying levels of familiarity with chemical concepts and the specific copper oxides in question.

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Homework Statement


Copper forms two oxides. For the same amount of copper, twice as much oxygen was used to form the first oxide than to form the second one. What is the ratio of the valencies of copper in the first and second oxides?

(This is not my homework question. I am solving a book on Mole Concept and i am asking questions from this book.)

Homework Equations





The Attempt at a Solution



I am not able to understand how should i start?



Thanks! :smile:
 
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Hi Pranav-Arora! :smile:

To understand and solve problems like these, the first step is always to find out what all the words mean.
Usually the solution to the problem becomes self evident then.

In your problem the word "valency" is used.
Do you know what it means?

Furthermore, it's about copper oxides.
Do you know which copper oxides they're probably talking about?
 
I like Serena said:
Hi Pranav-Arora! :smile:

To understand and solve problems like these, the first step is always to find out what all the words mean.
Usually the solution to the problem becomes self evident then.

In your problem the word "valency" is used.
Do you know what it means?

Furthermore, it's about copper oxides.
Do you know which copper oxides they're probably talking about?

Yes, i know what is valency. :smile:
Copper exists in two states Cu+2 and Cu+1 i.e. the ratio of the valency is 2:1.
In the book also it is given 2:1 and a hint is also given "Assume that oxides are Cu2Ox and Cu2Oy."
I want to know is there no significance of "twice as much oxygen"?
 
Pranav-Arora said:
Yes, i know what is valency. :smile:
Copper exists in two states Cu+2 and Cu+1 i.e. the ratio of the valency is 2:1.
In the book also it is given 2:1 and a hint is also given "Assume that oxides are Cu2Ox and Cu2Oy."
I want to know is there no significance of "twice as much oxygen"?

Right! :smile:
Well, if we would make no assumptions about the copper states (and actually there are more than the 2 you mentioned), we could still give the ratio of the valencies due to the fact it uses "twice as much oxygen".
I think there is nothing more to it than that. ;)
 
Last edited:
There is one more hint in the question that we can use "Rule 6".
In the book Rule 6 is:-

"For a compound MxNy, x moles of N = y moles of M"

I want to know how this equation is derived?
 
Pranav-Arora said:
There is one more hint in the question that we can use "Rule 6".
In the book Rule 6 is:-

"For a compound MxNy, x moles of N = y moles of M"

I want to know how this equation is derived?

That is not an equation.
It's like saying apples are equal to pears. ;)

I can only make wild guesses to what they mean.

What I can say is that in a compound like Fe2O3, you have Fe3+ and O2-.
So 1 mole of Fe2O3 consists of 2 moles Fe3+ and 3 moles O2- and their valencies ratio is 3:2.
But I suspect you already knew all that. :smile:
 
I like Serena said:
That is not an equation.
It's like saying apples are equal to pears. ;)

I can only make wild guesses to what they mean.

What I can say is that in a compound like Fe2O3, you have Fe3+ and O2-.
So 1 mole of Fe2O3 consists of 2 moles Fe3+ and 3 moles O2- and their valencies ratio is 3:2.
But I suspect you already knew all that. :smile:

The rule is "For a compound, MxNy, y*moles of M = x*moles of N"
For instance, we take Fe2O3, according to the rule, 3 * moles of O = 2 * moles of Fe.
I am not able to understand how this comes out?
 
Pranav-Arora said:
The rule is "For a compound, MxNy, y*moles of M = x*moles of N"
For instance, we take Fe2O3, according to the rule, 3 * moles of O = 2 * moles of Fe.
I am not able to understand how this comes out?

I think it's a typo.
Can I assume this is about the definition of a mole?


I think it should say something like:
1 mole of MxNy = x moles of M + y moles of N​


Or as a possible reaction:
x M + y N → MxNy
meaning you need x moles of M and y moles of N to create 1 mole of MxNy


Sorry, can't offer anything else.
 
Assume Fe2O3 is made of Fe3+ and O2-. Molecules are neutral (in terms of charge). Do you see now where the "rule" comes from?
 
  • #10
I like Serena said:
I think it's a typo.
Can I assume this is about the definition of a mole?


I think it should say something like:
1 mole of MxNy = x moles of M + y moles of N​


Or as a possible reaction:
x M + y N → MxNy
meaning you need x moles of M and y moles of N to create 1 mole of MxNy


Sorry, can't offer anything else.

There is no typo in the rule. My teacher proved it also but i forgot how he did it. Moreover, my teacher is not present currently in my city so i can't ask him also. :frown:

Borek said:
Assume Fe2O3 is made of Fe3+ and O2-. Molecules are neutral (in terms of charge). Do you see now where the "rule" comes from?

Firstly, Congratulatios on becoming the PF admin. :biggrin:

I still didn't get it.
 
  • #11
Borek said:
Assume Fe2O3 is made of Fe3+ and O2-. Molecules are neutral (in terms of charge). Do you see now where the "rule" comes from?

Pranav-Arora said:
I still didn't get it.

@Borek: I don't get it either.
I can only see that the valency-ratio is the inverse of the mole-ratio...

Oh and sorry for my somewhat slighting comment on chemistry in the "I love physics" thread.
*Hides from Borek*

(Hope you don't mind seeing me here. It's my first post in chemistry! :wink:)
 
  • #12
Sorry, I obviously switched indexes. You are right - there is something fishy about that rule.
 
  • #13
Borek said:
Sorry, I obviously switched indexes. You are right - there is something fishy about that rule.

So please tell me how can i prove it?
 

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