Difficulty with a basic motion problem

[frankfjf]

This time I'm having trouble with this problem:

If the position of an object is given by x = 2.30t^5, where x is measured in meters and t in seconds, find (a) the average velocity and (b) the average acceleration between t = 1.0 s and t = 2.0 s. Then find (c) the instantaneous velocity v and (d) the instantaneous acceleration a at t = 1.0 s. Next find (e) v and (f) a at t = 2.0 s.

I have solved a, but am uncertain how to obtain the two velocities needed for b according to the formula for average velocity. What do I need to do?

 

[lightgrav]

the velocity function is the time-derivative of the location function.

the acceleration function is the time-derivative of the velocity function.

 

[aud11888]

the average velocity forumula is [f(b)-f(a)]/b-a, the avg. acceleration formula is essentially the same except that for the values of f(b) and f(a) you need to take the derrivative of the position equation to give the velocity values

 

[lightgrav]

aud11888 means that average velocity = $$\frac{x(t_b) - x(t_a)} {t_b - t_a}$$