- #1

Amaretto

- 5

- 0

- Homework Statement
- Two friends build a ramp with a 10° angle at both Sides of the shore in between is a creek. The travel with a Velocity of 7m/s where the acceleration is capped so they always drive 7m/s. What distance do they travel when they drive over the ramp? No Air resistance Nor friction. My Language is bad, I'm not native

- Relevant Equations
- g=9.81m/s^2

x(t)=x0+v0*t+1/2*a*t^2

b=10°

I created a Vector which describes the direction of the medium. with r=(x(t),y(t))=((x0+cos(b)*t+0*t^2/2),(y0+sin(b)*t-9.81*t^2/2))

I created a vector for the acceleration a=(0,-9.81)

Now only the y(t) is relevant since x(t)

acceleration is zero. sin,cos describe the direction of the velocity without acceleration.

Now i wanted to set y0=0 and find where y=0. Because i think thats the moment he lands. I solved 0=0+t*sin(10°)-9.81t^2/2 to find t and got 0.0355s put that into s=v*t and got like 25cm. I think there`s something wrong. What do yall think?

I created a vector for the acceleration a=(0,-9.81)

Now only the y(t) is relevant since x(t)

acceleration is zero. sin,cos describe the direction of the velocity without acceleration.

Now i wanted to set y0=0 and find where y=0. Because i think thats the moment he lands. I solved 0=0+t*sin(10°)-9.81t^2/2 to find t and got 0.0355s put that into s=v*t and got like 25cm. I think there`s something wrong. What do yall think?