Why does the strong nuclear force become repulsive at small distances?

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The discussion centers on the strong nuclear force and its repulsive nature at small distances, which is essential for preventing nuclear collapse. Participants explain that quantum mechanics, particularly the Heisenberg uncertainty principle, plays a crucial role in this phenomenon, as it limits the probability of particles collapsing into a nucleus. The repulsive force is attributed to the Pauli exclusion principle, which prevents quarks from occupying the same space. Additionally, the concept of zero-point motion is mentioned as a factor in the stability of nucleons. Overall, the conversation highlights the interplay between quantum mechanics and nuclear stability.
Hootenanny
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This isn't a traditional homework question but here goes. I asked my physics tutor (A-Level) how the strong nuclear force becomes repulsive at small distances and he said he didn't know. I know that it is a nessecity that it is repulsive to prevent the nucleus collapsing, but I would like to know howit happens, are there any law's or mathematical derivations to prove this?

Any help / explanations would be great!
 
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Hootenanny said:
This isn't a traditional homework question but here goes. I asked my physics tutor (A-Level) how the strong nuclear force becomes repulsive at small distances and he said he didn't know. I know that it is a nessecity that it is repulsive to prevent the nucleus collapsing, but I would like to know howit happens, are there any law's or mathematical derivations to prove this?

Any help / explanations would be great!
I'll take a stab at it. But you really should be talking to ZapperZ.

I would also suggest this be moved to the High energy, Nuclear, Particle physics section.

What makes you think that the strong force becomes repulsive at small distances? The reason the nucleus does not collapse is similar to the reason an atom does not collapse (negative electrons do not fall into the positive nucleus). It has to do with quantum mechanics. It does not require the concept of a force to keep the quarks apart or the electrons and protons apart.

If the electron fell into the nucleus, we would know its position to within a very small \Delta x. So, the Heisenberg uncertainty principle says that its momentum range would be enormous. But this would require a huge amount of energy. Hence the probability that the electron will fall to the nucleus on its own is practically 0. Similarly, the energy required to collapse the three quarks in a nucleon is really enormous so the probability of nucleon collapse on its own is virtually 0.

But as I say, talk to ZapperZ.

AM
 
Thank's the reason I think that it becomes negative is because of the graphs shown in my textbook, something similar to this;
http://webs.mn.catholic.edu.au/physics/emery/assets/9_5_op21.gif
I understand what you mean about the uncertainty principle though, has it got something to do with zero point motion?
 
It is generally believed that the N-N potential has a hard repulsive core.
There have been attempts to get this with vector meson exchanges, but it is more easily seen as the Pauli principle for the quarks.
You can't put six quarks that close together.
The hard core has little to do with nuclear stability.
That is no different than hydrogen atom stability.
They both come from the lowest quantum state having a finite size.
 

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