Solving Friction Problem: 3.15 kg Block & 87.4 N Force

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SUMMARY

The discussion focuses on calculating the coefficient of kinetic friction for a 3.15 kg block subjected to an 87.4 N force at an angle of 58.9° while accelerating at 5.49 m/s². The relevant equation used is Ff = uN, where Ff represents the frictional force and N is the normal force. Participants emphasize the importance of drawing a free-body diagram to visualize forces and applying Newton's second law to solve for the normal force and subsequently the coefficient of friction.

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Homework Statement


A 3.15 kg block is pushed along the ceiling with a constant applied force of F = 87.4 N that acts at an angle of alpha = 58.9° with the horizontal, as seen in the figure below.
http://aycu26.webshots.com/image/18345/2003241655315981977_rs.jpg
The block accelerates to the right at 5.49 m/s2. Determine the coefficient of kinetic friction between block and ceiling.



Homework Equations


Ff=uN


The Attempt at a Solution



Tried using the angle but don't know what to do.
Any ideas?
 
Physics news on Phys.org
So what did you use for N? You need to show more of what you did. Have you drawn a diagram with all of the forces on it? Remember Newton's second law.
 

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