Find the frictional force between a block and a wall

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Homework Help Overview

The problem involves a block weighing 22 N that is pushed against a vertical wall by a force of 60 N at an angle of 30° above the horizontal. The coefficients of static and kinetic friction between the block and the wall are provided, and the goal is to determine the frictional force acting on the block.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the normal force and the static friction force, questioning whether the static friction force equals the product of the coefficient of static friction and the normal force.

Discussion Status

Participants are exploring the concept of static friction and its relationship to the normal force. Some hints have been provided regarding the nature of static friction, but there is no explicit consensus on the correct approach or solution at this time.

Contextual Notes

There appears to be some confusion regarding the calculation of the frictional force, as indicated by the original poster's mention of an incorrect value. The discussion also highlights the importance of understanding the conditions under which static friction operates.

isukatphysics69
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PHYSICSBLOCKWALL.PNG
1. Homework Statement

A block weighing 22 N is pushed against a vertical wall by a force of magnitude 60 N directed 30° above the horizontal. The block is intitally at rest. The coefficient of static friction between the wall and the block is 0.55 and the coefficient of kinetic friction between them is 0.38.What is the force of friction between the block and the wall? Express your answer as positive if the force of friction points up.

Homework Equations


f=m*a

The Attempt at a Solution


netforcey = 60sin(30)-mg+0.55*normalforce
netforcex = 60cos(30)-normalforce
since the block is not moving in x direction a = 0 so normalforce=60cos(30)
since looking for just friction and block initially at rest normalforce*staticfrictioncoefficient = friction force
since gravity point down friction force point up 0.55*normalfoce = 29 NEWTONSi didn't mean to post pic with -29 NEWTONS i meant 29 NEWTONS but either way still wrong
 

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Hint: ##\mu_s N## does not necessarily equal the static friction force. Why not?
(Here ##N## represents the normal force.)
 
TSny said:
Hint: ##\mu_s N## does not necessarily equal the static friction force. Why not?
(Here ##N## represents the normal force.)
because static friction just has to be less than or equal to μsN?
 
isukatphysics69 said:
because static friction just has to be less than or equal to μsN?
Yes. Good.
 
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TSny said:
Yes. Good.
OK got it the static friction is -8N thank you
 
:thumbup:
 

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