Question form Peskin Schroeder

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SUMMARY

The discussion focuses on the derivation of the right-hand side of formula 5.94 from its left-hand side in the context of Peskin and Schroeder's work on quantum field theory. The left-hand side is expressed as \(\frac{2 \pi \alpha^2}{4E^2 + 4E \omega \cos \theta}\), utilizing the relation \(e^2 = 16 \pi^2 \alpha^2\). The right-hand side is obtained by applying an exact expression for \(E^2\) and a two-term approximation for \(E\). This derivation is crucial for understanding the approximations used in quantum field calculations.

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Sorry for bothering...
How does righthand side of formula 5.94 is derived from its left handside after some approximation?
Probably it is very simple question but I could't get that expression:confused:

Thank u very much
 

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Using e^2 = 16 \pi^2 \alpha^2, the left side is

\frac{2 \pi \alpha^2}{4E^2 + 4E \omega cos \theta}.

Now use an exact expression for E^2 and a two-term approximation to E to get the right side.
 
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