Vibrating a 75g Bungee Cord: Standing Wave Formation

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SUMMARY

The discussion centers on the formation of standing waves in a 75g bungee cord with an equilibrium length of 1.20 m, stretched to 1.80 m and vibrated at 20 Hz, resulting in two antinodes. The participant attempted to calculate the spring constant 'k' using the formula w = sqrt(k/m) but encountered discrepancies in their results, obtaining values of 1184 N/m, double, and half of that. The correct approach to find 'k' involves ensuring accurate mass and frequency values are used in the calculations.

PREREQUISITES
  • Understanding of wave mechanics and standing waves
  • Familiarity with the formula w = sqrt(k/m)
  • Basic knowledge of mass and spring constant relationships
  • Experience with harmonic motion and frequency calculations
NEXT STEPS
  • Review the derivation of the wave equation for standing waves
  • Learn about the relationship between frequency, tension, and wave speed
  • Explore methods for calculating spring constants in elastic materials
  • Investigate the effects of mass on wave formation in stretched cords
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators and anyone involved in practical applications of harmonic motion and wave phenomena.

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Homework Statement


A 75 g bungee cord has an equilibrium length of 1.20 m. The cord is stretched to a length of 1.80 m, then vibrated at 20 Hz. This produces a standing wave with two antinodes.


Homework Equations


I really am not sure how to approach this using an equation, tried to use

w = sqrt (k/m)


The Attempt at a Solution



using the above equation I got a value of

1184 N/m for 'k', which is incorrect
 
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i'm getting now double of that, and half of that value, anyone have any ideas still? this assignment is due 12:00pm tomorrow for us
 

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