Need help finding spring constant

Click For Summary

Homework Help Overview

The discussion revolves around calculating the spring constant (k) for a scenario involving a ball dropped onto a spring. The ball's mass, drop height, and maximum spring compression are provided, alongside gravitational acceleration.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to apply the conservation of energy principle using the equation mgh = 0.5kx^2 but encounters difficulties. Participants question the correct height to use in the equation and suggest considering the change in gravitational potential energy.

Discussion Status

Participants are actively engaging in clarifying the approach to the problem. Some guidance has been offered regarding the height to use in calculations, with suggestions to measure from the lowest point of the spring's compression.

Contextual Notes

There is an ongoing discussion about the appropriate reference point for height in the energy conservation equation, indicating potential confusion about the setup of the problem.

Mustrdhead
Messages
4
Reaction score
0

Homework Statement



A 147g ball is dropped from a height of 56.5cm above a spring of neglibible mass. The ball compresses the spring to a maximum displacement of 4.45393cm. The acceleration is 9.8m/s^2. calculate the spring force constant k. Answer in units of N/m.

Homework Equations



Not sure


The Attempt at a Solution



I converted the mass from 147g to .147kg the height from 56.5cm to .565m and the displacement from 4.45393cm to .0445393m.

Now I am stuck and don't know what to do

I tried mgh=.5kx^2 but didnt work
 
Physics news on Phys.org
Mustrdhead said:
I tried mgh=.5kx^2 but didnt work
What did you use for h? (You need the change in height, from initial position to final position.)
 
what do you mean? i used the given height of .565m
 
Hint: What's the change in gravitational PE? Hint 2: Measure gravitational PE from the lowest point.
 
so use a zero height? or use .565+.0445393?
 
Mustrdhead said:
or use .565+.0445393?
That's the height you need to use in that formula. This is just a consequence of conservation of energy.
 
Thanks you are a genius
 
Mustrdhead said:
Thanks you are a genius
You are very perceptive. :smile:
 

Similar threads

Replies
17
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
8
Views
6K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 58 ·
2
Replies
58
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K