- #1
Master J
- 219
- 0
So in my book, it derives the expression for power in a traveling transverse mechanical wave.
P= Sqrt[(mu)F].(omega)^2.(A)^2
It reduces this from: P=k^2.omega^2.F.A^2.(sin(kx-omega.t)^2
Where all symbols are the standard ones in dealing with waves.
Could someone please go thru how it got from 2 to 1? I can't see the logic. I'm sure its obviously just basic math I am overlooking, but there may be a misprint in the derivation.
Cheers!
P= Sqrt[(mu)F].(omega)^2.(A)^2
It reduces this from: P=k^2.omega^2.F.A^2.(sin(kx-omega.t)^2
Where all symbols are the standard ones in dealing with waves.
Could someone please go thru how it got from 2 to 1? I can't see the logic. I'm sure its obviously just basic math I am overlooking, but there may be a misprint in the derivation.
Cheers!