Matt's Momentum After Jumping from Skateboard

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The discussion centers on the application of the conservation of momentum principle to determine Matt's velocity after jumping off his skateboard. Initially, Matt is moving at 4.00 m/s, and upon jumping backward, he kicks the skateboard forward at 8.00 m/s. By applying the conservation of momentum formula, the final velocity of Matt as he lands is calculated to be approximately 4.49 m/s. This calculation confirms the effectiveness of momentum conservation in analyzing motion in physics.

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Matt is gliding on his skateboard at 4.00 m/s. He suddenly jumps backward off the skateboard, kicking the skateboard forward at 8.00 m/s. Matt's mass is 50 kg and the skateboard's mass is 7 kg. How fast is Matt going as his feet hit the ground?

I have no idea where to begin. Should I first find the change in momentum?
 
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All you have to do is use conservation of momentum:

[tex]p_{final} = p_{initial}[/tex]
 
Is this right

BLaH! said:
All you have to do is use conservation of momentum:

[tex]p_{final} = p_{initial}[/tex]

v_f(50kg + 7kg) = 50kg*4m/s + 7kg*4m/s
v_f = 4.49m/s ?
 

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