Calculating Velocity after Skateboard Jump - A Physics Problem

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SUMMARY

The discussion focuses on calculating Dan's velocity after he jumps off his skateboard using the equation vf - vi = vexplosion * ln(mf/mi). Given that Dan's initial velocity (vi) is 3.00 m/s, his mass (mf) is 40.0 kg, and the skateboard's mass is 5.00 kg, the correct final velocity (vf) is determined to be 2.63 m/s. The user incorrectly used 6.00 m/s for vexplosion, which led to an incorrect calculation of 2.29 m/s. The proper application of the equation is crucial for accurate results.

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Homework Statement


Dan is gliding on his skateboard at 3.00m/s . He suddenly jumps backward off the skateboard, kicking the skateboard forward at 6.00m/s (as measured by an observer on the ground). Dan's mass is 40.0kg and the skateboard's mass is 5.00kg . How fast is Dan going as his feet hit the ground?

Homework Equations


vf-vi=vexplosion*ln(mf/mi)

The Attempt at a Solution


vi=3 m/s
mi=45 kg
mf of dan=40 kg
I used 6 m/s as vex
when I plugged the above in the equation to find vf I got 2.29 which was marked wrong. Is it wrong to use 6m/s for Vex?
 
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The correct answer is 2.63 m/s, but I'm still confused on the process to get the answer
 

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