Contextuality and Non-Locality

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Every contextual state is nonlocal, but not every nonlocal state is contextual, as illustrated by the spin of a single particle. The discussion centers on the relationship between contextuality and nonlocality, particularly in the context of quantum entanglement and the CHSH test. Nonlocality is considered a specific form of contextuality, but contextuality encompasses a broader range of phenomena. The existence of nonlocal yet non-contextual spin-1/2 states further supports this distinction. Overall, the conversation highlights the nuanced interplay between these two concepts in quantum mechanics.
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Every state that is contextual is nonlocal.

...and the inverse, is every state that is nonlocal is contextual ?
 
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audioloop said:
Every state that is contextual is nonlocal.
Not true. For example, spin of a single particle is contextual, but not nonlocal.
 
Demystifier said:
Not true. For example, spin of a single particle is , but not nonlocal.

talking about entanglement.the question is really for the second proposition (vinculated), the first is assumed from the beggining...that every state that is contextual with respect to the defined test of contextuality is nonlocal as per the CHSH test, but the converse is not true..non locality like a form of contextuality.
 
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mutually agree.
contextuality is broader, subsumes nonlocality.
same thing in quantum information (nonlocality is a generic feature of non-signaling).Existence of two spin-1/2 states that are non-local yet non-contextual.
http://arxiv.org/pdf/1207.1952v1.pdf
 
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Thread 'Angular Momentum Vector and Its Magnitude'

For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...
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