How to rank random function from smallest to largest with inverse f included?

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SUMMARY

The discussion focuses on ranking the values of a function and its inverse based on a provided graph of y=f(x). The values to rank are f−1(0), f(0), f(5), and f−1(5). The correct ranking is established as follows: f−1(0) is 1, f(5) is 2, f(0) is 3, and f−1(5) is 4. The key takeaway is the understanding that f(0)=4 implies f−1(4)=0, clarifying the relationship between a function and its inverse.

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Homework Statement



The graph of y=f(x) is shown below.

http://Newton.science.sfu.ca/cgi-bin/plot.png?file=public_public_1346904771_18810161_plot.data
Rank the following from smallest(1) to largest(4).

f−1(0)
f(0)
f(5)
f−1(5)

Homework Equations



none available

The Attempt at a Solution



f−1(0) 1
f(0) 3
f(5) 2
f−1(5) 4


Because if f(0) is 4, wouldn't that make the co-ordinates (0,4) so inverse would be (4, 0) so inverse f(0) would be 0 no? But I know this is wrong. I don't what I am doing wrong.
Please help
 
Last edited by a moderator:
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Knowing that f(0)= 4 tells you that f^{-1}(4)= 0, not f ^{-1}(0). What you need is some x such that f(x)= 0. Where is f(x)= 0 on your graph?
 

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