Injection on QxQ: Is f(a^2+b^2)=(lal,lbl) Well-Defined?

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The discussion centers on the function f defined as f(a^2+b^2) = (|a|, |b|) for a, b in Q. It raises the question of whether this function is well-defined and injective, given that multiple pairs (a, b) can yield the same value for a^2 + b^2. The initial confusion stems from the realization that f could produce different outputs for the same input, such as f(4) resulting in either (2, 0) or (0, 2). After correcting the definition to f(a^2+b^2) = |a| + |b|, the poster suggests that this new formulation makes the function injective. The discussion highlights the importance of clarity in defining functions to ensure they are well-defined and injective.
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I just want to ask.

For the set {a^2+b^2 , a,b \in Q}. Am i then right in saying that the map:

f(a^2+b^2)=(lal,lbl) is an injection on QxQ (the absolute values are there to make sure f is well-defined)? And is this how you write a thing like this formally.
 
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Your function is not well defined - note that a2+b2 is always an element of Q if a and b are, so you are saying f(x) = (|a|,|b|) for any way that I can pick a and b to write x = a2+b2. There are generally going to be multiple ways to write x in this way, for example
4 = 02 + 22 = 22 + 02,

so is f(4) supposed to be (2,0) or (0,2)?
 
ugh I see I made a mistake:
What I meant was:
f(a^2+b^2)=lal+lbl
now f is injective right?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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