How do astronomers measure an objects angular size?

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Discussion Overview

The discussion revolves around the methods astronomers use to measure the angular size of celestial objects, specifically using Jupiter as an example. Participants explore the calculations involved in determining angular size, including the necessary formulas and unit conversions.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant presents Jupiter's diameter and distance from Earth, seeking assistance with the calculation of its angular size.
  • Another participant provides the formula for angular size, \(\theta = 2 \arctan{\frac{r}{d}}\), where \(r\) is the radius and \(d\) is the distance.
  • A further clarification is made that in the small-angle approximation, the formula simplifies to \(\theta = \frac{2r}{d}\), with a note on unit conversion between radians and arcseconds.
  • One participant expresses confusion over their calculation, arriving at an angular size of 19.114 arcseconds and questioning whether they need to multiply by 2.
  • Another participant suggests dividing the diameter by the distance and converting to arcseconds using the factor 206265.
  • A participant confirms their calculation of 39.429 arcseconds but seeks clarification on the origin of the number 206265.
  • Further explanation is provided regarding the conversion factor from radians to arcseconds, linking it to the definition of an arcsecond in relation to astronomical distances.

Areas of Agreement / Disagreement

Participants generally agree on the formulas and methods for calculating angular size, but there are differing interpretations and calculations regarding the specific values and the application of the formulas.

Contextual Notes

Some participants express uncertainty about the calculations and the conversion factors used, indicating potential limitations in their understanding or application of the formulas.

Vast
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Lets use Jupiter which has a diameter of 142,984 km at a distance from Earth of 5 AU or 747,989,353 km. The answer should be around 40.0 arcseconds, I’m just having trouble understanding how to do the calculation. If someone could help it would be much appreciated.
 
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[tex]\theta = 2 \arctan{\frac{r}{d}}[/tex]

Where [itex]r[/itex] is the radius of the body and [itex]d[/itex] is the distance to the body.
 
Janus said:
[tex]\theta = 2 \arctan{\frac{r}{d}}[/tex]

Which of course reduces to [itex]\theta = 2r / d[/itex] (where [itex]\theta[/itex] comes out in radians) in the small-angle approximation, which surely holds for Jupiter viewed from the Earth (or even the moon or sun viewed from the earth).

And then you have to convert units as necessary, e.g. between radians and arcseconds.
 
I’m getting about 19.114. Is that right? Which would be arcseconds, not in radians, so I shouldn’t need to convert? What am I doing wrong? Unless, I just need to multiply it by 2?
 
Last edited:
Vast said:
I’m getting about 19.114. Is that right? Which would be arcseconds, not in radians, so I shouldn’t need to convert? What am I doing wrong? Unless, I just need to multiply it by 2?

The number you gave is the diameter, which is already twice the radius, so all you should need to do is divide those two numbers and then convert to arcseconds:

[tex]\theta_{arcseconds}=\frac{diameter}{distance}\times206265[/tex]
 
Thanks SpaceTiger. I got 39.429 seconds of arc, but I’m not sure where you got the number 206265 from. Can you explain that?
 
Vast said:
Thanks SpaceTiger. I got 39.429 seconds of arc, but I’m not sure where you got the number 206265 from. Can you explain that?

It's just the factor of conversion from radians to arcseconds. An arcsecond is equal to the angle subtended by earth-sun distance (AU) at a distance of parsec, so another way to write this is:

[tex]\theta_{arcseconds}=\frac{diameter_J}{distance_J}*\frac{parsec}{earth-sun~distance}[/tex]

where the "J" subscripts denote quantities for Jupiter. It's just a set of units that are convenient for interstellar scales. Note that a parsec is of order the distance to the nearest star. Also note that it was the parsec that was defined from the arcsecond and AU. An arcsecond can also be converted from radians by remembering that it's just 1/60 of an arcminute, which is 1/60 of a degree, which is 1/360 of a full rotation (2*pi radians).
 
Last edited:
Ok, I now see how that number is arrived at. Thanks for the explanation.
 

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