New study shows Dark Matter isn't needed? Relativty explains it?

AI Thread Summary
A new study suggests that dark matter may not be necessary to explain galactic rotation, arguing that general relativity (GR) can account for observed dynamics without invoking dark matter halos. Critics point out that the study has not yet undergone peer review and may contain errors, particularly in its reliance on non-linear GR rather than traditional Newtonian dynamics. The authors claim that when properly analyzed, the dynamics of galaxies align with mass density distributions, eliminating the need for dark matter. However, some participants in the discussion highlight existing evidence for dark matter, such as gravitational lensing in galaxy clusters. The implications of this study could challenge mainstream models of galaxy formation and the understanding of gravity itself.
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new study shows Dark Matter mat not exist? Relativty explains it?

Look here
http://www.space.com/scienceastronomy/051010_dark_matter.html"

Is this valid reasoning? I noticed it hadn't been submitted to peer review.
 
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Astronomy news on Phys.org
General Relativity Resolves Galactic Rotation Without Exotic Dark Matter has been submitted to Ap.J. it will be interesting to see if it passes peer review.

The case it makes is obvious; that the dynamics of a diffuse collection of orbiting masses, such as a spiral galaxy, has to be calculated in the non-linear theory of GR rather than the linear Newtonian theory. Apparently, and surprisingly, this has not been done before and the consequent mismatch between galactic dynamics and Newtonian theory has led to the invocation of galactic halo DM. However, Cooperstock and Tieu claim that when properly calculated there is no mis-match at all!.
However, in dismissing general relativity in favor of Newtonian gravitational theory for the study of galactic dynamics, insufficient attention has been paid to the fact that the stars that compose the galaxies are essentially in motion under gravity alone (“gravitationally bound”). It has been known since the time of Eddington that the gravitationally bound problem in general relativity is an intrinsically non-linear problem even when the conditions are such that the field is weak and the motions are non-relativistic, at least in the time-dependent case. Most significantly, we have found that under these conditions, the general relativistic analysis of the problem is also non-linear for the stationary (non-time-dependent) case at hand. Thus the intrinsically linear Newtonian-based approach used to this point has been inadequate for the description of the galactic dynamics and Einstein’s general relativity should be brought into the analysis within the framework of established gravitational theory. This is anessential departure from conventional thinking on the subject and it leads to major consequences as we discuss in what follows. We will demonstrate that via general relativity, the generating potentials producing the observed flattened galactic rotation curves are necessarily linked to the mass density distributions of the flattened disks, obviating any necessity for dark matter halos in the total galactic composition.

I think their calculations appear sound, although I have not checked them throroughly. However they conclude:
Moreover, it will be of interest to extend this general relativistic approach to the other relevant areas of astrophysics with the aim of determining whether there is any scope remaining for the presence of any exotic dark matter in the universe. Clearly the absence of such exotic dark matter would have considerable significance.
I cannot concur with the absence of DM as there is other evidence for extra-galactic DM from lensing and other effects in rich cluster IGM. However it may not be exotic, if Omegabaryon ~ 0.2 - 0.3, there would be no need to invoke hypothetical exotic non-baryonic DM to explain the mass detected within galactic clusters. Such a high Omegabaryon is predicted by the strictly linear expansion model.

Garth
 
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Again:- If this analysis by Cooperstock and Tieu stands up then it would have profound implications for the 'mainstream model'. In particular there would be a problem with galaxy formation within the time scale that model allows.

The present model relies on the quick concentration of non-interacting DM to form the potential wells into which baryonic matter can fall, which then forms the visible galaxies. However if these galactic haloes are only an artifact of inappropriate Newtonian dynamics then more time would be required for the galaxies, now seen at high z to form.

The most extreme example of this is the Hubble ultra deep field object UDF033238.7-274839.8 aka HUDF-JD2 , a 6 x 1011Msolar galaxy at z = 6.5 when the universe was only 860 Myrs old, (age given by Ned Wright's calculator allowing for DE). Also we have high-z quasars with significant iron abundances, and iron is the last element to be formed in fusion processes, such as APM 08279+5255at z = 3.91 whose age is 2.1 Gyr when the universe was only 1.6 Gyrs old (according to LCDM model expansion).

The strictly linear expansion model gives a universe age of 2 to 3 times the LCDM model.

Garth
 
Personally I suspect that the answer lies in the manner of Operation of Gravity, which is, to this date, seemingly, still unknown, in Completeness.

It may simply be that intergalactic gravity behaves slightly dfferently then the observable gravitational interactions seen at our local scale.

It may sum differently, it may simply be that in summing, it can drag much more of space around with it then had ever been previously thought of, if it can drag space around, then it can also drag around the contents of that space around without, persay, energy loss or general interactivity.
 
Lapin Dormant said:
Personally I suspect that the answer lies in the manner of Operation of Gravity, which is, to this date, seemingly, still unknown, in Completeness.

It may simply be that intergalactic gravity behaves slightly dfferently then the observable gravitational interactions seen at our local scale.

It may sum differently, it may simply be that in summing, it can drag much more of space around with it then had ever been previously thought of, if it can drag space around, then it can also drag around the contents of that space around without, persay, energy loss or general interactivity.
You'll need to express your ideas with a mathematically described testable theory, GR, MOND and SCC are such examples.

But first we have to get the GR analysis right!

Garth
 
Really :rolleyes: so words won't do for you, interesting as that is the foundation of Mathematics, words.

ana one ana two ana three .. .. .. .. ..

But I appreciate your answer, for what it is worth. :approve:
 
Lapin Dormant said:
Really :rolleyes: so words won't do for you, interesting as that is the foundation of Mathematics, words.

ana one ana two ana three .. .. .. .. ..

But I appreciate your answer, for what it is worth. :approve:
Your concepts are fine, as points for discussion, but they will need to be quantified and not just 'hand waving'. I'm not criticising, my hands 'wave' as much as anybody's! However, having a mathematically described theory that makes testable predictions is way we separate out those ideas that 'work' and reflect reality in some way from those that are to fall by the wayside.

Modified gravity is MOND and your "if it can drag space around" is the gravitomagnetic effect being tested at this moment by Gravity Probe B, who knows what its answer will be?

Garth
 
There has been a rebuttal of the paper that you can see here. The rebuttal basically says that the model is "unphysical". It's yet to be seen if this "unphysical" explanation is substantial or not.
 
  • #10
Pyro said:
There has been a rebuttal of the paper that you can see here. The rebuttal basically says that the model is "unphysical". It's yet to be seen if this "unphysical" explanation is substantial or not.
Welcome to these Forums Pyro! And thank you for that link.
We argue that in this model the gravitational field is generated not only by the galaxy matter, but by a thin, singular disk as well. The model should therefore be considered unphysical.
In fact I do not agree with its conclusion that the Cooperstock & Tieu galaxy model is 'unphysical', the galaxy does have a disk - the galactic disk in which the spiral arms are embedded, it consists of stars, dust and gas including massive molecular clouds. The total galactic mass Cooperstock & Tieu require is 21×1010M which is totally realistic.

Garth
 
  • #11
O.K. here it is, mathematically.

Garth said:
Your concepts are fine, as points for discussion, but they will need to be quantified and not just 'hand waving'. I'm not criticising, my hands 'wave' as much as anybody's! However, having a mathematically described theory that makes testable predictions is way we separate out those ideas that 'work' and reflect reality in some way from those that are to fall by the wayside.
Modified gravity is MOND and your "if it can drag space around" is the gravitomagnetic effect being tested at this moment by Gravity Probe B, who knows what its answer will be?

Garth
Thanks, I was aware of how science gets done, the answer mathematically would be ∞ = 1 (No, I am NOT joking) which needs to be broken down to be effective in it's descripton of reality, otherwise, no one will understand it, it needs explaining, sorry, but it is done with words, first, then math.

As Einstein himself stated, "Theory is that which shows us where to look" if I have a theory that is, ostensibly, complete and therefore shows 'what is' as such, then thereafter it would-could be mathematized, as to show it's validity, just that I do believe that it is not as simple as just one equation.

The concepts I have in my head are not based upon mathematical reasonings, {Persay thought they include math knowledge} they are based upon observation{s} of reality and Lots of Currently known Scienctific evidence, after all, there is ony about ten percent of it left to know.

LD
.. .. .. .. Hops off .. .. .. .. .. Stage .. .. .. .. [/color]...[/color] {Whoooops!} .. .. .. .. .. ..I'll get off of this thread now, go find turtle, he should be back, any moment now[/color]
 
  • #12
has to be calculated in the non-linear theory of GR rather than the linear Newtonian theory.

W00t? I was under the impression that astronomers/astrophysists always used GR, I mean you'd think that there is a significant difference between the two when you're talking about these kind of things.

I'm shocked that no one has done this before.
 
  • #13
Lapin Dormant said:
Thanks, I was aware of how science gets done, the answer mathematically would be ∞ = 1 (No, I am NOT joking) which needs to be broken down to be effective in it's descripton of reality, otherwise, no one will understand it, it needs explaining, sorry, but it is done with words, first, then math.
Agreed, words describe what the symbols represent in a mathematical formulation. The mathematical formulation part is what appears to be missing in this example.
 
  • #14
Pyro said:
There has been a rebuttal of the paper that you can see here. The rebuttal basically says that the model is "unphysical". It's yet to be seen if this "unphysical" explanation is substantial or not.

:smile:

I love how the rebuttal paper cites "Introduction to Relativity". I'll let you guys know if we ever find dust disks distributed as a delta function in z.
 
  • #15
SpaceTiger said:
:smile:
I love how the rebuttal paper cites "Introduction to Relativity".

:smile:

Actually, isn't it possible that this singular disk models the galaxy quite good? Would a more realistic model really give a much different result? (I'm asking because I don't know...)
 
  • #16
EL said:
:smile:
Actually, isn't it possible that this singular disk models the galaxy quite good? Would a more realistic model really give a much different result? (I'm asking because I don't know...)
I concur that's my point - even if their analysis leaves something to be desired the necessity of using GR rather than Newton to predict galactic rotation profiles would seem basic, don't you think?

Garth
 
  • #17
EL said:
:smile:
Actually, isn't it possible that this singular disk models the galaxy quite good? Would a more realistic model really give a much different result? (I'm asking because I don't know...)

In some spiral galaxies, there are disks that are relatively thin, but certainly not well-approximated by a delta function. The point in the rebuttal paper was that there was an extra source of gravity in addition to that which they were using to model the luminous matter of a "real" galaxy. In other words, they were unknowingly including dark matter. :smile:

As for your latter question, I'm relatively sure (though I've not done the calculations myself) that the Newtonian approximation will be valid if GR is properly applied.
 
  • #18
SpaceTiger said:
In some spiral galaxies, there are disks that are relatively thin, but certainly not well-approximated by a delta function. The point in the rebuttal paper was that there was an extra source of gravity in addition to that which they were using to model the luminous matter of a "real" galaxy. In other words, they were unknowingly including dark matter. :smile:
Ah, that explains a lot! Thanks. (Have to admit I didn't read the rebuttal too carefully.)


As for your latter question, I'm relatively sure (though I've not done the calculations myself) that the Newtonian approximation will be valid if GR is properly applied.
Yes, that's what I think too.

Anyway, it's strange that CERN newsletter took it up after the rebuttal was written...
http://science.slashdot.org/science/...tid=160&tid=14
 
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  • #19
I'm going to hide behind the skirt here, Garth... Can we say with any confidence what disc model might work? I think the observational evidence is really thin. Another objection: since when did CERN jump into the fray? I don't think that is even relevant to this conversation.
 
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  • #20
EL said:
Anyway, it's strange that CERN put it on their webpage after the rebuttal was written...

Yeah, we were just talking about this at (very late) dinner. One of the guys here says he knows the people that wrote the CERN article and he says they're pretty distant from the mainstream. I wouldn't take it as an endorsement by everyone at CERN and, to my knowledge, nobody in the mainstream is taking it seriously.
 
  • #21
Chronos said:
I'm going to hide behind the skirt here, Garth... Can we say with any confidence what disc model might work? I think the observational evidence is really thin.
As SpaceTiger pointed out, the model of the shape of the galaxy is really not the problem. The problem is that they seem to have invoked an extra source of gravity they didn't mean too...
 
  • #22
SpaceTiger said:
I wouldn't take it as an endorsement by everyone at CERN and, to my knowledge, nobody in the mainstream is taking it seriously.

Yes, that I'm pretty sure of too. Can we see the paper as debunked now, or do you think there could be some errors in the debunking?
 
  • #23
EL said:
Yes, that I'm pretty sure of too. Can we see the paper as debunked now, or do you think there could be some errors in the debunking?
Well, I pretty much ignored it from the get-go. There were two reasons for that. The first was that, if it were true, it would only explain one small part of the dark matter problem, leaving the rest horribly inconsistent. In other words, the same amount of dark matter that's needed to solve the dynamical problems is that needed to solve the problems of structure formation and the CMB power spectrum. If one part were solved in some other way, we would be left hanging on the other two.

The other reason was that I have a good bit of faith in the people that do these models. This is a pretty simple issue to have overlooked for so many years. I wouldn't be surprised if the same calculation had been done correctly many times before by other folks.

Anyway, yeah, it's debunked in my mind.
 
  • #24
O.k.

Chronos said:
Agreed, words describe what the symbols represent in a mathematical formulation. The mathematical formulation part is what appears to be missing in this example.
Agreed so I would need the Latex equivalent of "The sum of all things, going to infinity, is equal to one"

But as I had already acknowledge it needs elucidation {mathematically as well} to fit into the minds of everyone else.

Till then, I will, probably, just shut up, Thanks
 
  • #25
curious

SpaceTiger said:
In some spiral galaxies, there are disks that are relatively thin, but certainly not well-approximated by a delta function. The point in the rebuttal paper was that there was an extra source of gravity in addition to that which they were using to model the luminous matter of a "real" galaxy. In other words, they were unknowingly including dark matter. :smile:
Just a question from the curious, is it not possible that gravity acts in some manner unseen to-or by us that could afford it a Disc of energy-alone that is {somehow} dragging around the rest of the Galaxy, with a variant in it's function pertinant to the elementals, timely available, of the construct of any given galaxy, calculated not 'across the board' of known galaxies but taking into account the relative ages, as per distribution, of the See-therefore 'known' galaxies and-or their respective centers?
Just a question, mind you.
 
  • #26
Lapin Dormant said:
Just a question from the curious, is it not possible that gravity acts in some manner unseen to-or by us that could afford it a Disc of energy-alone that is {somehow} dragging around the rest of the Galaxy

Gravity acting in a manner that we can't see is called philosophy. Gravity acting in a manner inconsistent with GR is possible only in the regimes in which the theory has not been tested. This includes the strong field and cosmological limits.


with a variant in it's function pertinant to the elementals

The "elementals" were, as far as I know, done away with in science hundreds of years ago.


timely available, of the construct of any given galaxy, calculated not 'across the board' of known galaxies but taking into account the relative ages, as per distribution, of the See-therefore 'known' galaxies and-or their respective centers?

Astronomers always make the appropriate considerations for age when taking their measurements. Of course, one can create arbitrarily complicated theories which are consistent with the observations and invoke, for example, time variations in the laws of physics. However, these theories will have no predictive power.
 
  • #27
SpaceTiger said:
Gravity acting in a manner that we can't see is called philosophy. Gravity acting in a manner inconsistent with GR is possible only in the regimes in which the theory has not been tested. This includes the strong field and cosmological limits.
The "elementals" were, as far as I know, done away with in science hundreds of years ago.
Astronomers always make the appropriate considerations for age when taking their measurements. Of course, one can create arbitrarily complicated theories which are consistent with the observations and invoke, for example, time variations in the laws of physics. However, these theories will have no predictive power.
Gravity already acts in a Manner that we cannot "see", what we "see" is the resultant of gravities Force acting-at work. A stationary car {Parked} is gravity acting, and no one can "see" it doing it, although you can, in your head, 'envision' it.

"Elementals" refers to the reality of elements of Chemistry, (Periodic table of elements) as the state of matter, temperature and type of Atom-molecule (Ergo Composition) might just have more effect, gravitationally, then is currently thought, or known.
No need of time variation in the laws of physics, simply the notation that what is Observed, 13.5 Billion Light years away, is also that NEW.

Therefore perhaps operating on-in a manner that is yet not understood, from this perspective, as this perspective is where we have taken all of our Known {current} 'rules of physics' from, not from "there".
Could be some {very} Slight Differences we don't realize just yet, the View has some obscuring factors to it, doesn't it.
 
  • #28
Luminesence?

Lets try it this way, take a gas cloud 20 K in diameter, G^M/r so we will use M = 1 so all we have left is G/r {By the way there was an experiment, done in Germany, wherein the value of G has been brought into question, back in the 90's Last century (I love saying that)} so I will run into our gas cloud with a heating source, {this is, after all, a 'thought experiment', so I can do that, "run into a Gas cloud"} release several thousands of thousands of caloric values (BTU's) and the gas cloud will, upon the timing of the radiant exchange factors relevant to the type of Gas that it is, {Which chemical element(al) it actually is} expand it's r value, so does it's potential G/r value change, as well?

"What is there" {Liqid-solid-gas} is just as important, if not moreso, to "how it is functioning" as 'How it is functioning' is Based upon What is there!
Does that bring more "light" to your understanding of it?
 
  • #29
It's just "so" last Century

Whoops, got to fix some of this, the Gas cloud is 20 Kms, it's supposed to be G^m/r {not M the capitalisation} and let's say that when I expanded the Gas cloud (No Jokes about that :-p please ) it became 40 Kms in Dia.

Asks' us the Question of; "Did the G value actually reduce, by half, of what it was-had been, even though our Mass has remained-remains the same?"

This question is so "last century" I' :!) saying that :approve: :-p :-p
 
  • #30
Lapin Dormant said:
Gravity already acts in a Manner that we cannot "see", what we "see" is the resultant of gravities Force acting-at work. A stationary car {Parked} is gravity acting, and no one can "see" it doing it, although you can, in your head, 'envision' it.

No, that's a measurable effect. In science, we're only concerned with measurable effects. If that's not what you mean by what we can "see", then I can assure that the distinction you're making is scientifically uninteresting.

"Elementals" refers to the reality of elements of Chemistry, (Periodic table of elements) as the state of matter, temperature and type of Atom-molecule (Ergo Composition) might just have more effect, gravitationally, then is currently thought, or known.

The noun form of "elemental" is not used in that way, so please use the word "element" in the future if you want people to understand you. Nobody is going to think that you're unintelligent if you use the standard meanings of words.

No need of time variation in the laws of physics, simply the notation that what is Observed, 13.5 Billion Light years away, is also that NEW.
Therefore perhaps operating on-in a manner that is yet not understood, from this perspective, as this perspective is where we have taken all of our Known {current} 'rules of physics' from, not from "there".
Could be some {very} Slight Differences we don't realize just yet, the View has some obscuring factors to it, doesn't it.

No idea what you're trying to say. The same applies to your other posts, which read more like a philosophy text than a scientific query. You need to be more precise if you wish to understand something scientific. For example, sentences like the following:

What is there" {Liqid-solid-gas} is just as important, if not moreso, to "how it is functioning" as 'How it is functioning' is Based upon What is there!

This would be completely ignored by most scientists if asked to them. I'm willing to make an attempt at answering your question, but you need to be more specific. The one question that sort of makes sense is the following:

Which chemical element(al) it actually is} expand it's r value, so does it's potential G/r value change, as well?

If a cloud of constant mass and density expands to a larger radius, then yes, its potential energy increases (all of the elements expand in approximately the same way). If you mean the gravitational potential on the surface, then your formula is correct. If you mean the total potential energy of the cloud, then it's given by:

U=\frac{3}{5}\frac{GM^2}{r}
 
  • #32
Sorry a bit 'off thread' but

SpaceTiger said:
No, that's a measurable effect. In science, we're only concerned with measurable effects. If that's not what you mean by what we can "see", then I can assure that the distinction you're making is scientifically uninteresting.

What I mean by 'See' is simply that you cannot see {Visualy} that gravity is acting in an on-going-persistent-incessant fashion-manner as to keep that car attached to the ground, Unmoving, and you cannot "see" it doing that, "see" as in OBSERVE {Visually} the energy at work.

If you have a Problem with the idea of "invisible things" {'things' like energy} you cannot see radiation either, so use a gieger counter and be scientific.

That you personally express that as something that you find "scientifically uninteresting" is to me more your loss then anything else.

SpaceTiger said:
The noun form of "elemental" is not used in that way, so please use the word "element" in the future if you want people to understand you. Nobody is going to think that you're unintelligent if you use the standard meanings of words.
Now you are making me laugh, forgive me, but I find this rather condescending, in tone. {Langauge instructions?}

SpaceTiger said:
No idea what you're trying to say. The same applies to your other posts, which read more like a philosophy text than a scientific query. You need to be more precise if you wish to understand something scientific. For example, sentences like the following:
Firstly what leads you to believe that I am making only 'queries'? nevermind you seem to miss that all science is Philosophically based, from it's outset, as it is a System of 'beliefs-theories' that attempts to use certain standards, scientific Methodology, as proof of those beliefs-theories. Concensus to that 'belief' {Theory} is acknowledged when evidenced by the ability of Observational-testable-repetitively experimentation concords from readings of 'Physical' things, like atoms.

After that, as you admit you have "NO idea" of what I am saying, I'll re-iterate it, with some additions as to endevour to Make it clear to you

Lapin Dormant said:
No need of time variation in the laws of physics, simply the notation that what is Observed, 13.5 Billion Light years away, is also that NEW.
Means that what we currently see is "New" in the sense that it is the Beginning of the Universe from a Point of View of 'Time'.[/color]

Therefore perhaps operating on-in a manner that is yet not understood, from this perspective, as this perspective is where we have taken all of our Known {current} 'rules of physics' from, not from "there".
All of what we currently know is from Local Space respective of Having Tested the Properties of Physical Space, Light speed might be Different Just outside of the Local Vicinity, we have not yet, and can not, yet, test that. That would Change Many things.[/color]

Could be some {very} Slight Differences we don't realize just yet, the View has some obscuring factors to it, doesn't it.

In the one page, you referred me to, respective of the Conversation you had with Turbot, you mentioned that (1+z) that z=1000 and-or z=1200 would not be observed, here, locally, as it has become obscured, right?
That is what I am referring to, that, and some other 'notions' that apply.[/color]

Now, you follow up with this

Lapin Dormant said:
What is there" {Liqid-solid-gas} is just as important, if not moreso, to "how it is functioning" as 'How it is functioning' is Based upon What is there!

SpaceTiger said:
This would be completely ignored by most scientists if asked to them. I'm willing to make an attempt at answering your question, but you need to be more specific. The one question that sort of makes sense is the following:

Please look, and read, what I had posted as a "quotation of Myself" Above, and your responce, as it is not a question, it is a Statement. That you cannot find the 'sense' in it, not my fault, also the Idea that you seem to think that you can respond in the stead of "Most scientists, well rather assumptive of you, isn't it? perhaps condescending again?

Lapin Dormant said:
Which chemical element(al) it actually is} expand it's r value, so does it's potential G/r value change, as well?
<Quite a partiallity of citation of what I had written, and with 'no name' ascribed, that is simply lazy.

SpaceTiger said:
If a cloud of constant mass and density expands to a larger radius, then yes, its potential energy increases (all of the elements expand in approximately the same way). If you mean the gravitational potential on the surface, then your formula is correct. If you mean the total potential energy of the cloud, then it's given by:
Sorry but I have emboldened your words as I now need Clarification from you, as you State that, "If a cloud of constant mass and density expands to a larger radius, then yes," [/color] Please tell me how a Cloud can retain a CONSTANT DENSITY and CONSTANT MASS and expand, in VOLUME? cause I am at a COMPLETE loss as to how that works.

Then you tell me "If you mean the gravitational potential on the surface, then your formula is correct." [/color] It would, otherwise be amusing, but laughing at you now would be rude, BECAUSE the "Formula" that you Claim I am Using, please remember, I asked you a QUESTION, is not the Right answer, as increasing the radius of the Cloud will space out the Atoms and their gravitational Interactivety as per the measure of "Gravitational Action at a Distance" therefore the Activity dropping off at the SQUARE of the Distance, so the Proportionate Amount of Negation of the Superficial Gravitational Effect would be FOUR TIMES, or x 4 or Gm/4r

Thereafter, I had NOT queried you for this responce " If you mean the total potential energy of the cloud, then it's given by:"[/color]

Not the Total Potential energy of the cloud, but the measure of it's gravitational effect on any other given Mass, as measured from it's "surface" I HAD been Specific, as you seemed to be seeking.

SO, I 'googled' your equation, something like this u = (3/5)(GM^2/r)
and Found a website Merlyn.demon.Co-Uk wherein under this title "Binding Energy" we find your equation derived as thus:
© Dr J R Stockton said:
The binding energy, U, of a sphere (of mass M and radius R) is the energy required to move all of its particles to infinity in different directions; it is given by U = 3/5GM2/R.

To calculate U, one can dismantle the sphere shell by shell and integrate; from the above, the energy dU required to move a shell of thickness dr and mass dm to infinity from a surface at radius r and local gravity g is given by dU = g r dm. We have g = GM(r/R)3/r2 and dm = M×3r2dr/R3 (volume increases thrice as fast as radius, relatively). Thus
U = ò0R [ GM(r/R)3/r2 × r × 3Mr2dr/R3 ]
U = 3 G M 2 / R6 × ò0R [ r4dr ] = 3/5 GM2/R

So we read what the gentleman writes and we find that he seems to think that; "(volume increases thrice as fast as radius, relatively)" so I go to this website W3 .aaamath. com to verify that I have the Correct formula for the calculations of the Volume of Spheres, do the Math using 4/3πr3 such that, at an r value of 20 the answer works out to 33510.3216, and at an r value double that, 40 the answer is 33510.3216 which is an eightfold change in volume.

Can you see a problem there? {and My Apologies to Dr J R Stockton, just that}

Although I can clearly see that you can type well, as in this thread CMB it would appear that typing the Words "I Do Not {currently} Know the Answer to that Question" doesn't seem to flow, from your mind, to your fingers, and it would seem that even the attempt at evading the Correct responce by pointing at a Power metric, was founded in Flawed Information, so it would seem that your not a thorough on your "references" either.

As you may be able to tell, saying "I didn't know" is what you were supposed to write in that last post.

If you would like to measure, as a "Dynamic measure" the 'Force' acting upon the parked car, then simply get yourself a Michaelson Morely Interferometer, and Point the "Two light pathways" perpendicular to the Ground, you will get a Quite Dynamic reading of the Invisible force, of Gravity, as it is Acting.

Perhaps, after that, you will do me a small favor, and not respond, to anything, I write, any further.

Good thing I agreed "Not to" a priori.

LD
.....walks...off...head down...saddened...[/color]
 
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  • #33
ever heard of private messaging?
 
  • #34
Lapin Dormant said:
What I mean by 'See' is simply that you cannot see {Visualy} that gravity is acting in an on-going-persistent-incessant fashion-manner as to keep that car attached to the ground, Unmoving, and you cannot "see" it doing that, "see" as in OBSERVE {Visually} the energy at work.

See my first response. This is basically equivalent to hypothesizing a correction to gravity (or perhaps another force). In order to achieve the balance you're describing, gravity and electromagnetism are inducing equal and opposite forces on the car. In the case of a star, the only force we know of that can act on it in any significant way is gravity... and we have a law for how that behaves.

If you have a Problem with the idea of "invisible things" {'things' like energy} you cannot see radiation either, so use a gieger counter and be scientific.
Read what I said again:

In science, we're only concerned with measurable effects. If that's not what you mean by what we can "see", then I can assure that the distinction you're making is scientifically uninteresting.

Both energy and radiation are measurable, so no, I wouldn't find them scientifically uninteresting.

also the Idea that you seem to think that you can respond in the stead of "Most scientists, well rather assumptive of you, isn't it? perhaps condescending again?

Unless you're a scientist, how would you know? Perhaps if you were, the statement would be plainly obvious.
If you were to walk onto a construction site, would you be upset if the workers lectured you on the use of their equipment? Would it be condescending that they assumed you weren't as familiar as they in their area of expertise?

Sorry but I have emboldened your words as I now need Clarification from you, as you State that, "If a cloud of constant mass and density expands to a larger radius, then yes," [/color] Please tell me how a Cloud can retain a CONSTANT DENSITY and CONSTANT MASS and expand, in VOLUME? cause I am at a COMPLETE loss as to how that works.

Constant density in space, not time. That is, the cloud has one spatially constant density before expanding and another afterwards. This is only to simplify the computation of the potential/binding energy. Other spatial dependences of density will give a different constant out front, but will be of the same character (proportional to M2 and 1/R).

Then you tell me "If you mean the gravitational potential on the surface, then your formula is correct." [/color] It would, otherwise be amusing, but laughing at you now would be rude, BECAUSE the "Formula" that you Claim I am Using, please remember, I asked you a QUESTION, is not the Right answer, as increasing the radius of the Cloud will space out the Atoms and their gravitational Interactivety as per the measure of "Gravitational Action at a Distance" therefore the Activity dropping off at the SQUARE of the Distance, so the Proportionate Amount of Negation of the Superficial Gravitational Effect would be FOUR TIMES, or x 4 or Gm/4r

Let's review the basic gravitational formulae:

F=\frac{GMm}{r^2}
\Phi=\frac{GM}{r}
U=\frac{3}{5}\frac{GM^2}{R}

The first is the magnitude of the force on a mass, m, a distance r from the cloud center. The second (which is what you had in your post), is the magnitude of the gravitational potential at a distance, r, from the cloud center. The last is the magnitude of the potential/binding energy of the cloud, where I substituted R to represent the total radius of the cloud. Please note that r=R only if you're evaluating the the force or potential at the surface of the cloud.

If you double the radius of the cloud, the first and second quantities stay the same unless you're moving the point at which you evaluate them. If you evaluate them both at the surface, the force will fall by a factor of a quarter, the potential by a factor of a half. The last equation is a property of the cloud itself, so it does not have a point of evaluation. Doubling the radius will then reduce that quantity by a factor of a half.

Hopefully this will clear up your misunderstanding.
 
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  • #35
matt.o said:
ever heard of private messaging?
Yes, I have!
 
  • #36
matt.o said:
ever heard of private messaging?
And if you read the Guidelines you will know that it is NOT private, Not at all.

Funny too, your public profile wouldn't let me read any of your other postings, just a Ruse/psyeudonymforamentor name, are you?

LD
Don't Bother .. .. .. .. .. .. ThinksThanks .. .. .. .., ,.. .. .. I lept .. Figures, NOW it does .. .. .., ,.. .. .. lept again[/color]
 
  • #37
Bringing this thread back on topic...
Chronos said:
I'm going to hide behind the skirt here, Garth... Can we say with any confidence what disc model might work? I think the observational evidence is really thin. Another objection: since when did CERN jump into the fray? I don't think that is even relevant to this conversation.
No, we cannot say at the moment what disk model might work with pure GR, though I do think the infinitely thin disk of Cooperstock & Tieu is a workable rough approximation to the real situation.

The point is that until a proper GR analysis is done noboby will know whether any model might work.

However, as I posted in the S&GR forum "Overturning GR contest" thread, given that the mass in a galaxy is in orbit, rather than concentrated at the centre, GR's non-linear effects might well be significant. The orbiting mass's 'kinetic energy' contributes to the density and angular momentum terms of the stress-energy-momentum tensor Tuv which then generates more gravity (curvature) in a way that does not happen in Newtonian theory.

The onus is therefore on those who want to analyse galactic rotation profiles in the Newtonian approximation to prove that the non-linear terms are not significant.

AFAIK this has not been done. As I asked in the "Overturning GR contest" thread: "does anybody know of any previous work" where this has been published?
Garth
 
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  • #38
Garth said:
No, we cannot say at the moment what disk model might work with pure GR, though I do think the infinitely thin disk of Cooperstock & Tieu is a workable rough approximation to the real situation.

But, still the thing is that C&T happened to include a singular disk which they didn't mean to, i.e. their model includes an ADDITIONAL source of gravity APART FROM the ordinary matter in the galaxy.
If you would model the galaxy as simply an infinitely thin disk, you would not end up with the same rotation curves as they get in their paper.

Their additional thin disk acts as dark matter, and hence it is not that strange they get the correct rotation curves. They included DM without knowing it...
 
  • #39
EL said:
But, still the thing is that C&T happened to include a singular disk which they didn't mean to, i.e. their model includes an ADDITIONAL source of gravity APART FROM the ordinary matter in the galaxy.
If you would model the galaxy as simply an infinitely thin disk, you would not end up with the same rotation curves as they get in their paper.
Their additional thin disk acts as dark matter, and hence it is not that strange they get the correct rotation curves. They included DM without knowing it...
Hi EL! Thank you for your comment.

Yes I do understand what Korzynski is saying. He does not, however, indicate the total mass of this additional thin disk. I cannot believe it is as massive as the DM halo it replaces, 10X the baryonic mass, as it is all within the visible galaxy outer radius and it would affect stellar orbital periods too much. If it is only a small additional component to the total galaxy mass (Cooperstock's value 2.1 x 1011 Msolar) then it might be a reasonable model of the thin galactic disk observed (6 x 1010 Msolar).

My main point, however, is notwithstanding Cooperstock & Tieu model's validity, the non-linear GR effects may well be significant in galactic rotation profiles and should be investigated thoroughly.

Garth
 
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  • #40
But if you notice the Cooperstock Appendix you'll see their solution for density is
\rho=5.64 . 10^{-14}\frac{(N_r^2+N_z^2)}{r^2} kg/m3
so they are back to the old 1/r2 Newtonian flat rotation solution!
Garth
 
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  • #41
Garth said:
But if you notice the Cooperstock Appendix you'll see their solution for density is
\rho=5.64 . 10^{-14}\frac{(N_r^2+N_z^2)}{r^2} kg/m3
so they are back to the old 1/r2 Newtonian flat rotation solution!

It's not obvious to me that the above equation is even a close approximation to a 1/r^2 dependence, since N depends non-trivially on radius. Did you check this numerically?
 
  • #42
SpaceTiger said:
It's not obvious to me that the above equation is even a close approximation to a 1/r^2 dependence, since N depends non-trivially on radius. Did you check this numerically?
I was using a 'wand waving' OOM approximation:
As V(r, z)=\frac{3.10^8}{r}N(r, z) is more or less constant on the flat part of the rotation curve therefore approximately we can take
N(r, z) = A.V(r,z).r
and at constant z
\rho=5.64 . 10^{-14}\frac{(N_r^2+N_z^2)}{r^2} kg/m3
becomes
\rho=A_1 + A_2\frac{N_z^2}{r^2}
more or less the Newtonian model with appropriate values for the constants A1 and A2.
I hope this helps.
Garth
 
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  • #43
Garth said:
I was using a 'wand waving' OOM approximation:
As V(r, z)=\frac{3.10^8}{r}N(r, z) is more or less constant on the flat part of the rotation curve therefore approximately we can take
N(r, z) = A.V(r,z).r
and at constant z
\rho=5.64 . 10^{-14}\frac{(N_r^2+N_z^2)}{r^2} kg/m3
becomes
\rho=A_1 + A_2\frac{N_z^2}{r^2}
more or less the Newtonian model with appropriate values for the constants A1 and A2.
I hope this helps.

Well, firstly, take another look at your final equation. It says that the density approaches a constant value as the radius approaches infinity. This should give you a hint that something is wrong. The basic rotation curve that results from that equation is flat towards the center and then rises linearly as the first term becomes larger than the second term.

What it would seem you did is misinterpret the N_r^2 and N_z^2[/tex]. They&#039;re partial derivatives, so to take advantage of the flat rotation curve simplification, you have to differentiate V with respect to r like:<br /> <br /> \frac{dV}{dr}=AN_rr+AN_zr+AN(r,z)=0<br /> <br /> which leads to:<br /> <br /> N_r^2=(-N_z-\frac{V}{Ar^2})^2<br /> <br /> Plugging this into your density equation will still give you something non-trivial, I&#039;m afraid. Try reading the density profiles from their plots instead.<br /> <br /> Edit: Replaced V_r with \frac{dV}{dr} to make it clear that I was taking a total derivative, not a partial.
 
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  • #44
SpaceTiger said:
Well, firstly, take another look at your final equation. It says that the density approaches a constant value as the radius approaches infinity. This should give you a hint that something is wrong.
The Newtonian density function that delivers the flat rotation curve is:
\rho(r)=\frac{C_0}{(a^2+r^2)}
where C0=4.6x108Msolar and a = 2.8 kpc. of course the density distribution has to be truncated at some radius r = a0 otherwise the total galactic mass would be infinite. This is basic theory.

Cooperstock &Tieu discuss the matter quite extensively: “It is unknown how far the galactic disks extend. More data points beyond those provided thus far by observational astronomers would enable us to extend the velocity curves further. Presumably a point (let us call it rf ) is reached where we can set rho to zero. At this point, (2) no longer applies as there are no longer co-rotating fluid elements being tracked. As a result, (9) no longer applies and the w function is no longer constant. Beyond rf, no further mass is accumulated.“

There is also a change of regime as r tends to zero.

All I did was to give a very ‘rough and ready’ comparison, taking z to be a constant, therefore N becomes N(r), and also taking V to be a constant then N becomes linear in r and Nr a constant..

I was considering only the central ranges to show that \rho varies as r-2. The complete numerical calculation was done by Cooperstock & Tieu.

As I said the main question is whether the non-linear GR effects are significant in galactic rotation, and if so then what of galactic halo DM?

Garth
 
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  • #45
Garth said:
The Newtonian density function that delivers the flat rotation curve is:
\rho(r)=\frac{C_0}{(a^2+r^2)}
where C0=4.6x108Msolar and a = 2.8 kpc. of course the density distribution has to be truncated at some radius r = a0 otherwise the total galactic mass would be infinite. This is basic theory.

Come on Garth, you're just making this worse. First of all, that's not the relation you got in your above calculation:

A_1+\frac{A_2}{r^2} \ne \frac{B_1}{B_2+r^2}

for any constants A and B. You can see this by again looking at its limits. Your first expression goes to a constant density at infinity, while this new one goes to zero.

Secondly, that is not the expression to generate a flat rotation curve in Newtonian gravity, it's an expression for which the rotation curve asymptotes to flatness at infinity. A completely flat rotation curve comes from an isothermal sphere:

\rho=\frac{A}{r^2}


All I did was to give a very ‘rough and ready’ comparison, taking z to be a constant, therefore N becomes N(r), and also taking V to be a constant then N becomes linear in r and Nr a constant..

If this was what you did, it would be inconsistent with your result. That gives:

\rho = \frac{const.+N_z^2}{r^2}

Now, this is the Newtonian result if N_z is a constant with radius, but there's no reason to assume this should be the case. Taking the radial partial derivative at a constant z does not mean that partial of z is constant with r.
 
  • #46
SpaceTiger said:
\rho(r)=\frac{C_0}{(a^2+r^2)}
that is not the expression to generate a flat rotation curve in Newtonian gravity, it's an expression for which the rotation curve asymptotes to flatness at infinity.
It's the standard expression that delivers a flat velocity profile at large
r >> a, but modifies the isothermal sphere to give rigid-body rotation at small r << a.
A completely flat rotation curve comes from an isothermal sphere:
\rho=\frac{A}{r^2}
Which is what I was saying, I know that Nz is not constant in general - however it is zero if in a certain regime in the Cooperstock & Tieu relationship the orbital velocity is taken to be constant.
V (r, z) =\frac{3.10^8}{r}N(r, z)=constant

so N(r,z) = C.r

therefore Nr = C and Nz = 0,

my A1 should have been in fact zero (I answered the post hurriedly - thank you for correcting me) so the density expression does approximate to the isothermal sphere,
\rho=\frac{A}{r^2}

As I have been saying this is only my first approximation to the exact Cooperstock & Tieu equation, 'reverse engineering' it to see how it works and that it is consistent with the standard Newtonian theory. As I said, the equation must be solved properly as in fact they did. And they got that result without a massive external halo - just (with the Korzynski correction) of an extra infinitely thin disk, which might be modelling the observed thin galactic disk.

This diversion has taken attention away from the main question: as I have now raised several times:"Are the non-linear GR effects significant in galactic rotation, and if so, then what of galactic halo DM?"

Garth
 
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  • #47
Garth said:
"Are the non-linear GR effects significant in galactic rotation, and if so, then what of galactic halo DM?"
I would love to see this actually worked out in detail. My impression is that almost everyone (including myself) "feels" that the non-linear corrections would be unimportant, or at least not able to replace the dark matter, but that's of course not a reason why they should be so.
 
  • #48
Thank you EL, what do you think of the Cooperstock and Tieu approach to the problem? I am at a disadvantage in not being able to get a copy of their reference 6 - van Stockum, W.J., 1937. Proc. R. Soc. Edin. 57, 135, which appears to be quite important; does anybody know where it might be downloaded?

Having been rebutted maybe they will present a revised paper for publication during the refereeing process, but it would be unfortunate if such a paper were not accepted and the question of non-linear effects were simply forgotten.

Garth
 
  • #49
van Stockum's work is cited all over the 'net in the context of frame dragging, temporal anomalies, etc, but it does not appear that anybody has transcribed or scanned the original work for download.

Here's a paper that might be interesting to people studying DM distribution.

http://www.csun.edu/~vcphy00d/PDFPublications/2004 FDARB.pdf

We give examples of axially symmetric solutions to the field equations in which zero angular momentum test particles, with respect to nonrotating coordinate systems, acquire angular velocities in the opposite direction of rotation from the sources of the metrics. We refer to this phenomenon as “negative frame dragging.”
 
  • #50
I'm finding the Cooperstock and Tieu paper very hard to follow. The rebuttal paper is much clearer.

Assuming the rebutal paper is correct about the expression for N(r,z), it's very clear that
N_{z,z} is not well behaved at z=0, which leads me to believe the rebuttal paper. (That's the second partial of N(r,z) with respect to z, in case the notation isn't clear).

At this point, though, I am getting different results for the Einstein equation than Cooperstock and Tieu. I've tried a couple of different approaches

1) Ignore C&T's remarks about \bar{\Phi} and just find the Einstein equations for zero pressure in the coordinate basis.

2) Set up an orthonormal basis of one-forms that creates a diagonal metric, and calculate G with respect to this orthonormal basis. I *think* this is most likely what C&T means by a "local" transform. Unfortunately, I still get different results for the Einstein equation.

In the group of equations given in (5) in

http://arxiv.org/PS_cache/astro-ph/pdf/0507/0507619.pdf

the fourth equation follows from the first two, however I get a different result for the third equation.

<br /> (3 N^2+r^2)(N_r^2+N_z^2) + 2(N^2-r^2)(V_{r,r}+V_{z,z})<br />

It could easily be a mistake on my part. Then Van Stockum paper might help clear up what's going on (but I don't have easy access to it).
 
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