The Erdos-Straus Conjecture proposes that:
For n >= 1, 4/n = 1/a + 1/b + 1/c, has postive integer solutions.
n = 2k (evens)
n = 4k+3 (odds)
n = 4k+1 (odds)
For 2k I have found the pattern --> if k >= 1, 4/2k = 1/2k + 1/2k + 1/k. This is simple, I know.
I am having difficulty...