MHB (0,a) , (b,0) , (2,d) and (e,7) lie on y=2x+1, find a, b, d and e

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The equation of the line is y = 2x + 1, and the points (0, a), (b, 0), (2, d), and (e, 7) lie on this line. For the point (0, a), substituting x = 0 gives a = 1. For (b, 0), solving the equation 0 = 2b + 1 results in b = -0.5. For (2, d), substituting x = 2 yields d = 5, and for (e, 7), solving 7 = 2e + 1 gives e = 3. The values found are a = 1, b = -0.5, d = 5, and e = 3.
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A STRAIGHT LINE has equation y=2x+1. The point coordinates (0,a) , (b,0) , (2,d) and (e,7) lie on this line. Find the values of a,b,d, and e.
 
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Parthyy said:
A STRAIGHT LINE has equation y=2x+1. The point coordinates (0,a) , (b,0) , (2,d) and (e,7) lie on this line. Find the values of a,b,d, and e.
You have an equation y = 2x + 1 and several ordered pairs on that line.

So for the first, (0, a) we have
[math]a = 2(0) + 1 = 1[/math]

Thus a =1. Can you finish?

-Dan
 
Parthyy said:
A STRAIGHT LINE has equation y=2x+1. The point coordinates (0,a) , (b,0) , (2,d) and (e,7) lie on this line. Find the values of a,b,d, and e.
Each pair represents (x, y). The line is given as y= 2x+ 1 so (0, a) must satisy a= 2(0)+ 1. similarly, (b, 0) must satisfy 0= 2b+ 1. Solve that equation for b. (2, d) must satisfy d= 2(2)+ 1. (e, 7) must satisfy 7= 2e+ 1. Solve that equation for e.
 

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