1.3 Iridov - Find Time Interval ( Kinematics )

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Homework Help Overview

The problem involves kinematics, specifically analyzing the motion of a car that accelerates, moves uniformly, and then decelerates. The total time of motion is given as 25 seconds, with an average velocity of 72 km/h. The original poster seeks to determine the duration of the uniform motion phase.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • The original poster attempts to calculate the time spent in uniform motion but encounters an imaginary result in their calculations. Some participants suggest considering the area under the velocity-time graph, relating it to the average velocity and total distance traveled.

Discussion Status

Participants are exploring different methods to approach the problem, including graphical interpretations and algebraic manipulations. There is an ongoing examination of the calculations and assumptions made by the original poster, with some guidance offered regarding the use of trapezoidal area calculations.

Contextual Notes

There is mention of a graph that represents the velocity over time, and the original poster expresses uncertainty about their calculations, indicating a potential oversight in their reasoning. The discussion includes references to specific equations and relationships between distance and time.

razored
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Thank you for taking the time to read this lengthy post.

A car starts moving rectilinearly, first with acceleration a=5m/s2(the initial velocity is 0) then uniformly, and finally, decelerating at the same rate a, comes to stop.The total time of motion equals 25 seconds. The average velocity during whole time is 72 km/h. How long does the car move uniformly?WARNING : 2 MB IMAGE

http://img26.imageshack.us/img26/1403/defaultx.png" All my equations appear to be correct; however, when I calculate the t_{o}, I get an imaginary answer. What did I miss or do wrong?
 
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razored said:
Thank you for taking the time to read this lengthy post.

A car starts moving rectilinearly, first with acceleration a=5m/s2(the initial velocity is 0) then uniformly, and finally, decelerating at the same rate a, comes to stop.The total time of motion equals 25 seconds. The average velocity during whole time is 72 km/h. How long does the car move uniformly?

Maybe consider the area of a trapezoid?

That is what your V(t) graph represents.

You know that the integral of V(t) yields X(t)

They tell you what the area is ... avg V * total T = 20 * 25 = 500.

The base is 25 sec and total X is 500
So ...

(25+X)/2*H = 500

You also know that X = 25 - 2d
where d is the 2 periods of acceleration and deceleration.

And H = 5*d
where V = 5*t so ...

H = 5*(25 -X)/2

Combining things then yields:

5*(25 -X)/2*(25+X)/2 = 500

5/4*(252 - X2) = 500

I get a real result.
 
Actually, I ignored the graph I drew when I solved the problem because I realized(on another piece of paper) that the area I was calculating (two triangles and rectangle) was identical to D = 2x_o + x_1.

This may be asking too much but can you find the mistake in my work? I just don't see it.

Thanks again.
 
razored said:
Actually, I ignored the graph I drew when I solved the problem because I realized(on another piece of paper) that the area I was calculating (two triangles and rectangle) was identical to D = 2x_o + x_1.

This may be asking too much but can you find the mistake in my work? I just don't see it.

Thanks again.

Now that you know the answer, you can work backwards to figure the error in your math. In all honesty, I'm not that interested in looking.
 
EDIT : My mistake.
 
Last edited:

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