1) A rope 5m is fastened to two hooks 4m apart on a horizontal

  • Thread starter Thread starter verb tense
  • Start date Start date
  • Tags Tags
    Horizontal Rope
Click For Summary
SUMMARY

This discussion focuses on calculating tensions and forces in various physics scenarios involving ropes and poles. The first problem involves a 5m rope fastened to hooks 4m apart with a 10kg mass, requiring the calculation of tension in the rope segments of 3.0m and 2.0m. The second problem presents a 7m pole supported by two individuals, where a 20kg weight must be strategically placed to ensure one person supports three times the weight of the other. The third scenario examines the forces acting on a 100cm pole with a 2.6kg load, requiring calculations for vertical force applied by the hand and the force on the shoulder.

PREREQUISITES
  • Understanding of basic physics concepts such as tension and equilibrium
  • Knowledge of force calculations and moments in mechanics
  • Familiarity with the principles of static equilibrium
  • Ability to draw and interpret free-body diagrams
NEXT STEPS
  • Study the principles of tension in ropes and cables
  • Learn about static equilibrium and its applications in physics
  • Explore the calculation of moments and their significance in force analysis
  • Practice solving problems involving forces on beams and poles
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in mechanics, particularly those studying forces, tension, and equilibrium in static systems.

verb tense
Messages
19
Reaction score
1
1) A rope 5m is fastened to two hooks 4m apart on a horizontal ceiling. To the rope is attached a 10kg mass so that the segment of the rope are 3.0m and 2.0m.Compute the tension in the string.
2) A uniform pole 7m long weighing 10kg is supported by a boy 2m from one end and a man 3m from the other end. At what point must 20kg weight be attached so that the man would support thrice as much weight as the buy
3)A man carries a load of mass 2.6kg from one end of a uniform pole 100cm which has a mass 0.4kg the pole rests on his shoulder at a point 60cm from the load he holds it at the other hand what vertical force must be applied by his hand and what is the force on his shoulder.

Rule of equilibrium under parallel complanor force
Total downward forces = total upward forces
total anticlockwise moment= total clockwise moment
moment= force x perpendicular distance to line of action.
 
Physics news on Phys.org


My attempt
 

Attachments

  • Physics.jpg
    Physics.jpg
    13.3 KB · Views: 1,032


You have to imagine that you are hanging the mass as directed in the problem. Try to do that and you get the correct diagram.
 


OK but what's the formula for computing tension?
 


It all starts from the diagram according to the way I know how to do it.
 

Similar threads

Replies
26
Views
6K
  • · Replies 7 ·
Replies
7
Views
9K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
24
Views
8K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
Replies
1
Views
3K