1) A rope 5m is fastened to two hooks 4m apart on a horizontal

  • Thread starter Thread starter verb tense
  • Start date Start date
  • Tags Tags
    Horizontal Rope
Click For Summary

Homework Help Overview

The discussion revolves around problems related to forces, tension, and equilibrium in physics. The original poster presents multiple scenarios involving ropes, weights, and poles, requiring analysis of forces and moments.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the importance of visualizing the setup and creating diagrams to understand the problems better. There is a question about the formula for computing tension, indicating a need for clarification on the mathematical aspects involved.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the problems. Some guidance has been offered regarding the importance of diagrams, but there is no explicit consensus on the approaches to take or the formulas to use.

Contextual Notes

Participants are working under the constraints of homework rules, which may limit the information they can share or the methods they can discuss. The problems involve various assumptions about the setups and forces at play.

verb tense
Messages
19
Reaction score
1
1) A rope 5m is fastened to two hooks 4m apart on a horizontal ceiling. To the rope is attached a 10kg mass so that the segment of the rope are 3.0m and 2.0m.Compute the tension in the string.
2) A uniform pole 7m long weighing 10kg is supported by a boy 2m from one end and a man 3m from the other end. At what point must 20kg weight be attached so that the man would support thrice as much weight as the buy
3)A man carries a load of mass 2.6kg from one end of a uniform pole 100cm which has a mass 0.4kg the pole rests on his shoulder at a point 60cm from the load he holds it at the other hand what vertical force must be applied by his hand and what is the force on his shoulder.

Rule of equilibrium under parallel complanor force
Total downward forces = total upward forces
total anticlockwise moment= total clockwise moment
moment= force x perpendicular distance to line of action.
 
Physics news on Phys.org


My attempt
 

Attachments

  • Physics.jpg
    Physics.jpg
    13.3 KB · Views: 1,041


You have to imagine that you are hanging the mass as directed in the problem. Try to do that and you get the correct diagram.
 


OK but what's the formula for computing tension?
 


It all starts from the diagram according to the way I know how to do it.
 

Similar threads

Replies
26
Views
6K
  • · Replies 7 ·
Replies
7
Views
9K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
24
Views
8K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
2K
Replies
1
Views
3K