Hey, I've been working on this problem for quite a while now, and I can't seem to come up with the solution. I would love some help in the right direction. 1. The problem statement, all variables and given/known data Someone spots a flowerpot that sails first up and then down past an open window. The pot was in view for a total of 0.61 s, and the top-to-bottom height of the window is 2.25 m. How high above the window top did the flowerpot go? ttotal= .61 s Height = 2.25 m 2. Relevant equations Vf = Vi + axt Xf = Xi + 1/2(Vi + Vf)t 3. The attempt at a solution To try and solve it, I figured that if the pot was in view for .61s total, it was .305s on each trip. So I figured its Vi = 2.25m/.305s = 7.377 m/s. So if its Vi=7.37, then it would take .7527 seconds to slow to 0m/s due to -9.8m/s2 for gravity. After .7527 seconds it would fly to 2.77m, making it .53 meters above the window. Unfortunately, this is not the correct answer. Any suggestions?