Free-fall kinematics on a plane: Displacement from Window to Ground?

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SUMMARY

The discussion focuses on calculating the height of a window from which a ball is thrown vertically upward at an initial velocity of 10 m/s, hitting the ground after 5 seconds. Using the kinematic equation for displacement, Δd = Vi(Δt) + Δa(Δt)^2, the total displacement was calculated as 25 meters. The final velocity (Vf) was not needed for this specific calculation, confirming that the initial upward velocity and the time of flight were sufficient to determine the height. The problem was resolved outside the forum, indicating that the calculations were verified.

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Homework Statement


A ball is thrown vertically upward from a window at 10m/s. It hits the ground 5.0 seconds later. What is the height of the window from the ground?

Given
Vi = 10 m/s
Vf = 0
Δt = 5.0 m/s
Δa = -9.8 m/s^2

Find
Δd(w-g) = ?

Homework Equations



Δd = Vi(Δt) + Δa(Δt)^2

And the other four "kinematic equations"

The Attempt at a Solution



Total displacement:

Δd = ((vi + vf)/2)(Δt)

= (10/2)(5)
= 25 m
Not sure where to go from here and if I'm on the right track. Your help is greatly appreciated!

P.S. I apologize for the terrible formatting. I'll get it soon enough!
 
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