1-D Perfectly Elastic Collison PLEASE CHECK THANKS

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SUMMARY

The discussion centers on a 1-D perfectly elastic collision involving two masses, where mass m1 (0.3155 kg) moves at 17.6 m/s and collides with a stationary mass m2 (0.685 kg). Post-collision, m2 moves at 11.1 m/s, while m1 reverses direction with a velocity of -6.5 m/s. The conservation of momentum and kinetic energy principles confirm that the calculations are correct, as both momentum and kinetic energy are conserved before and after the collision.

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1-D Perfectly Elastic Collison PLEASE CHECK! THANKS

Homework Statement


Mass m1 is moving to the right at a velocity of 17.6m/s. Suddenly it strikes a stationary ball. The stationary ball has a mass of .685kg. The collision is perfectly elastic and 1 dimensional. The collision forces m2 to move to the right at 11.1m/s (v2prime).

Total momentum = 5.5 kg m/s ??
m1 = .3155kg ??
v1prime= -6.5m/s ??

Homework Equations



momentum before = momentum after
m1v1 = m1v1prime + m2v2prime

v2prime = (2m1)/(m1+m2) (v1) + (m2-m1)/(m1+m2) (v2)

v1prime = (m1-m2)/(m1+m2) (v1) + (2m2)/(m1+m2) (v2)

The Attempt at a Solution

11.1 = (2*m1)/(m1+.685) ( 17.6) + 0 (cancels cause m2 is stationary
11.1(m1+.685) = 35.2m
11.1m1 + 7.6035 = 35.2m
24.1m = 7.6035
m1= .3155 kg

v1prime = (.316-.685)/(.316+.685)(17.6) + 0 (v2 = 0)
v1prime = -6.50 m/s Left.

momentum before = momentum after
(17.6)(.316) = (.316)(-6.5) + (.685)(11.1)
5.55 kgm/s


Thanks for taking your time to help ! I just want to make sure this is right.
 
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yeah, it's right. to check just see if the momentum is the same before & after and check if the kinetic energy is the same before & after. they are, so you did it right.
 


sorry to ask this, but are you 100% sure? Maybe I can get some more people to assure this answer is correct, as there are multiple other ways of doing the same problem.
 


proxy98 said:
sorry to ask this, but are you 100% sure? Maybe I can get some more people to assure this answer is correct, as there are multiple other ways of doing the same problem.

Yes. there is only one solution to the problem, so if you plug it into find the correct results, it must be right.
 

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