1 gram of C3H8 gas and 1 gram of O2 gas are delivered

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SUMMARY

The discussion centers on the combustion of 1 gram of propane (C3H8) and 1 gram of oxygen (O2) in a 1-liter metal sphere, following the balanced chemical reaction C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(g). The limiting reagent is identified as propane, which is completely consumed, resulting in the formation of carbon dioxide and water vapor. After the reaction, the sphere is maintained at a temperature of 226.25 °C, and the final pressure is calculated using the ideal gas law, given the total moles of gas produced.

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  • Understanding of stoichiometry and limiting reagents in chemical reactions
  • Familiarity with the ideal gas law (PV=nRT)
  • Basic knowledge of gas behavior under varying temperature and pressure conditions
  • Ability to perform calculations involving moles and gas conversions
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Chemistry students, chemical engineers, and professionals involved in combustion processes will benefit from this discussion, particularly those focused on gas reactions and thermodynamics.

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1. 1 gram of C3H8 gas and 1 gram of O2 gas are delivered to a metal sphere with a fixed volume of 1 L. After the two gases are introduced, the two reactants are ignited and burned according to the balanced reaction: C3H8(g) + 5O2(g) 3CO2(g) + 4H2O(g)
After reaction, the sphere is held at 226.25 oC. What is the final pressure in the sphere given that all the compounds inside are gases and the limiting reagent is completely consumed with 100% yield ?




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1. Determine limiting reagent. Use the equation to find how much product there is and how much excess reagent.
2. Determine the total moles of gas, n, in the sphere.
3. Determine pressure in sphere. Since n, V, and T are known by this point, use ideal gas law.
 

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