100 animals 100 dollars? easy? I thought so.

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Discussion Overview

The discussion revolves around a mathematical problem involving the purchase of 100 animals for exactly 100 dollars, with specific constraints on the types and costs of animals (cows, pigs, and chickens). Participants explore various approaches to solve the problem, including algebraic formulations and trial-and-error methods.

Discussion Character

  • Mathematical reasoning, Homework-related, Debate/contested

Main Points Raised

  • One participant presents the problem and constraints, including equations for the total number of animals and total cost.
  • Another participant questions whether the total cost must equal $100.
  • A participant suggests using trial and error to find a solution, indicating uncertainty about the requirement to show work mathematically.
  • One participant provides a solution involving specific values for cows, pigs, and chickens, but another points out that this solution does not meet the total cost requirement.
  • There is a discussion about the implications of the cost of chickens and whether it must be a multiple of certain values, with conflicting views on this point.
  • Several participants propose different combinations of animals that satisfy the conditions, but there is no consensus on a single solution.
  • Participants express confusion over the correct interpretation of the cost of chickens, with some mistakenly using different values.
  • One participant acknowledges a mistake in their earlier calculations and updates their initial post to clarify their approach.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct solution to the problem. There are multiple competing views and proposed solutions, with ongoing debate about the implications of the costs and constraints.

Contextual Notes

There are unresolved issues regarding the interpretation of the cost of chickens and how it affects the overall solution. Some participants express uncertainty about the mathematical steps required to arrive at a valid answer.

Automagman
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I have to buy 100 animals, I have to use 100 dollars, I have to get at least 1 of each.

Cow(X) = 10 bucks
Pig(Y) = 1 buck
Chicken(Z) = .5 bucks, 50 cents, 2 quarters

This looked really easy at first but I kept getting stuck, how do I get through this?

Restraints I came up with.

x+y+z=100
10x+1y+.5z=100
X is greater than or equal to 1 and is less than or equal to 10
Y is greater than or equal to 1
Z is greater than or equal to 1
 
Last edited:
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does the total cost have to be $100 also??
 
i have the answer!

hint:

x (cows) can be reasonably guessed.

then you go from there

(this is how i did it. trial and error.lol)

only problem is, if you have to show work in terms of math, I am not sure.

i just tried out various values. took me a couple minutes.
 
Your system is fine. Solve it to get

x - \frac{z}{18} = 0, \; y + \frac{19}{18}z = 100

so you can choose z=18 \Longrightarrow x = 1, \; y = 81.
 
Data: so you can choose z=18,x=1,y=81
But, that fails to equal $100, since we have 10x1+1x81+.05x18 =$91.90.

Frankly, the number of chicken must be a multiple of 20, since the other monetary values are in dollars. Then while we are at it, the cost of the pigs and the chickens must be a multiple of $10.
 
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nope ... the number of chickens is not a multiple of 20
 
If the total cost is to be $100 how are we to get rid of the odd nickels if the chickens are not a multiple of 20? Are you planning to add a tax?
 
its not nickels, but $0.50
 
oops, i used $0.5 for z~

There's no positive integer z that also makes x and y positive integers that satisfies the system if it's really $0.005.
 
  • #10
at least for my answer and what he wrote above (.5) which i took as 50 cents
 
  • #11
i had a different answer

4 cows = $40
24 pigs = $24
72 chickens = $36
===============
100 animals at $100
 
  • #12
It's even worse than nickels. The way that he stated it it was half-pennies.
 
  • #13
Yes, there are several possible answers if a chicken costs $0.5.
 
  • #14
I get:

x,y,z
1, 81, 18
2, 62, 36
3, 43, 54
4, 24, 72
5, 5, 90
 
  • #15
woops, lol ahaha. I feel retarded. chickens are 50 cents, or 2 quarters. Wow sorry about that.

note- made a few changes to my first post to answer some of your questions
 
Last edited:

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