11th gr. chem (composition of a hydrate)

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SUMMARY

The discussion revolves around the calculation of the composition of a hydrate, specifically focusing on copper(II) sulfate pentahydrate (CuSO4·5H2O). The user initially calculated the percentage of water lost during the conversion to anhydrous copper(II) sulfate, arriving at 36%. However, confusion arose regarding the determination of the number of moles of water present in the hydrate. The correct approach involves using the formula CuSO4·XH2O, where 'X' must be determined from experimental data rather than assuming it to be 5.

PREREQUISITES
  • Understanding of molar mass calculations, specifically for CuSO4 and H2O.
  • Familiarity with the concept of hydrates and their empirical formulas.
  • Knowledge of stoichiometry and mole calculations in chemistry.
  • Ability to interpret laboratory data and perform post-analysis calculations.
NEXT STEPS
  • Review the process of determining the empirical formula from experimental data.
  • Learn how to calculate the number of moles of water in hydrates using the formula CuSO4·XH2O.
  • Study the principles of thermal decomposition of hydrates and their implications in laboratory settings.
  • Explore common mistakes in laboratory calculations and how to avoid them.
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Chemistry students, laboratory technicians, and educators involved in teaching or learning about the composition and analysis of hydrates.

monica_e826
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i might get confusing cause i don't understand this very much
but here is the copy of my lab i need help with #1 & 6 of the POST-ALAYSIS
here is the word doc. of my lab
http://courses.digitaldapp.org/documents/Inquiry Lab - Experiment 03 - Composition of a Hydrate.doc


btw.
5 grams of copper II sulfate was used
when it became an anyhride it had a mass of 0.15g


i know i made a mistake somewhere in my lab and i was wondering if you tell where my mistake is and what i should do. i would highly appreciate it.

so i know...
CuSO4 . 5H2O
molar weight is 249.69g


by itself is
CuSO4 = 159.61g
5H2O= 90.81

so i took the
mass of the water/total mass of hydrate x100= 36% of H2O removed in anhydrous copper (II) sulfate.

am i correct?
this is where i got confused...
-determine the # of moles of water present in each mole of hydrous copper (II) sulfate.
so what i did was:
5H2O

H10= 11%=11/1.0079=10.91=2
O5=88%=88/15.9994=5.5=1
is this the correct Empirical formula?
2H10O5 & can be simplified to 2H2O

so now what do i use to find the amount of moles of water present?
 
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monica_e826 said:
i might get confusing cause i don't understand this very much
but here is the copy of my lab i need help with #1 & 6 of the POST-ALAYSIS
here is the word doc. of my lab
http://courses.digitaldapp.org/documents/Inquiry Lab - Experiment 03 - Composition of a Hydrate.doc


btw.
5 grams of copper II sulfate was used
when it became an anyhride it had a mass of 0.15g

Are you sure you got that right? I assume that "it had a mass of..." means that the anhydride had a mass of... Is that right?


i know i made a mistake somewhere in my lab and i was wondering if you tell where my mistake is and what i should do. i would highly appreciate it.

so i know...
CuSO4 . 5H2O
molar weight is 249.69g


by itself is
CuSO4 = 159.61g
5H2O= 90.81

Good so far...

so i took the
mass of the water/total mass of hydrate x100= 36% of H2O removed in anhydrous copper (II) sulfate.

am i correct?
this is where i got confused...
-determine the # of moles of water present in each mole of hydrous copper (II) sulfate.
Here is where you strayed off course. The formula for your unknown hydrate is CuSO4 . XH2O. You need to solve for 'X', not assume that it is 5 and do some math without using any of the data you collected.

Show us the raw data you collected.
 

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