- #1
Aya
- 46
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calculate the precent by mass of water in a sample of hydrated copper (II) sulfate.
mass of beaker-165.3g
mass of beaker with bluestone-173.9g
mass of dehydrated bluestone-170.7g
Would this be a ballanced equation for this reaction?
CuSO4•5H2O+ heat= CuSO4+5H2O
so would you do this
%by mass=mass of part/mass of whole
=90.1g/249.7g/molx100
= 36%
is this correct?
mass of beaker-165.3g
mass of beaker with bluestone-173.9g
mass of dehydrated bluestone-170.7g
Would this be a ballanced equation for this reaction?
CuSO4•5H2O+ heat= CuSO4+5H2O
so would you do this
%by mass=mass of part/mass of whole
=90.1g/249.7g/molx100
= 36%
is this correct?