Calculating moment of inertia for a uniform rod of mass

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SUMMARY

The discussion focuses on calculating the moment of inertia for a uniform rod of mass M rotating about one end, with an additional point mass equal to M placed at the opposite end. The correct formula for the total moment of inertia is I = (MR^2)/3 + MR^2, where R is the length of the rod. It is crucial to apply the parallel axis theorem when combining the moments of inertia to ensure they are calculated with respect to the same axis.

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I have a uniform rod of mass M, which rotates about one of its ends, and a point mass equal to the mass of the rod is added to the other end.

To calculate the new moment of inertia, do I just need to add the moment of inertia of the rod and that of the point mass together?

i.e. I = (MR^2)/3 + MR^2 ?

Any help would be much appreciated.
 
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Yes you add them together, but make sure you add them together with respect to the same axis. Remember the parallel axis theorum.
 
Cheers for that.
 

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